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3 years ago

How far below sea level is the peak of the ridge?

Chemistry

1 answer:

mario62 [17]3 years ago

7 0

I think is 1 and a half km

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What are the classes of alkanol

LuckyWell [14K]

1-PRIMARY ALKANOL 2-SECONDARY ALKANOL 3-TERTIARY ALKANOL

8 0

3 years ago

What describes a mixture

kirill [66]

Answer:

a mixture is a material made up of two or more different substances which are physically combined.

4 0

3 years ago

Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it

lions [1.4K]

<u>Answer:</u> The equilibrium concentration of $COF_2$ is 0.332 M

<u>Explanation:</u>

We are given:

Initial concentration of $COF_2$ = 2.00 M

The given chemical equation follows:

$2COF_2(g)\rightleftharpoons CO_2(g)+CF_4(g)$

<u>Initial:</u> 2.00

<u>At eqllm:</u> 2.00-2x x x

The expression of $K_c$ for above equation follows:

$K_c=\frac{[CO_2][CF_4]}{[COF_2]^2}$

We are given:

$K_c=6.30$

Putting values in above expression, we get:

$6.30=\frac{x\times x}{(2.00-2x)^2}\\\\x=0.834,1.25$

Neglecting the value of x = 1.25 because equilibrium concentration of the reactant will becomes negative, which is not possible

So, equilibrium concentration of $COF_2=(2.00-2x)=[2.00-(2\times 0.834)]=0.332M$

Hence, the equilibrium concentration of $COF_2$ is 0.332 M

4 0

3 years ago

Calculate the Molarity when a 6.11 mL solution of 0.1 H2SO4 is diluted with 105.12 mL of water

barxatty [35]

Molarity after dilution : 0.0058 M

<h3>Further explanation </h3>

The number of moles before and after dilution is the same

The dilution formula

M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution

V₁ = volume of the solution before dilution

M₂ = Molarity of the solution after dilution

V₂ = Molarity volume of the solution after dilution

M₁=0.1 M

V₁=6.11

V₂=105.12

$\tt M_2=\dfrac{M_1.V_1}{V_2}=\dfrac{0.1\times 6.11}{105.12}=0.0058~M$

5 0

3 years ago

In the chemical reaction:

tiny-mole [99]

Answer:

Explanation:

6 0

1 year ago