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3 years ago

8

Steel is an alloy consisting of Fe with a small amount of C. Elemental Cr can be added to steel to make the steel less likely to

rust
a. True
b. False

1 answer:

Yakvenalex [24]3 years ago

8 0

The statement is true

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An oxide of aluminum contains 0.545 g of Al and 0.485 g of O. Find the empirical formula

uysha [10]

Answer:

The answer is: <u>Al2O3</u>

Explanation:

The data they give us is:

0.545 gr Al

0.485 gr O.

To find the empirical formula without knowing the grams of the compound, we find it per mole:

0.545 g Al * 1 mol Al / 27 g Al = 0.02 mol Al

0.485 g O * 1 mol O / 16 g O = 0.03 mol O

Then we must divide the results obtained by the lowest result, which in this case is 0.02:

0.02 mol Al / 0.02 = 1 Al

0.03 mol O / 0.02 = 1.5 O

Since both numbers have to give an integer, multiply by 2 until both remain integers:

1Al * 2 = 2Al

1.5O * 2 = 3O

Now the answer is given correctly:

Al2O3

8 0

3 years ago

Write the symbol for every chemical element that has atomic number greater than 55 and less than 140.8 u

patriot [66]

Answer on the picture

8 0

3 years ago

What point A on the phase diagram called?

Mariana [72]

Answer:

D) the critical point

Explanation:

Point A is the critical point in phase diagram. This is the highest temperature and pressure at which a pure material can exist in vapor/liquid equilibrium. Pretty cool!

6 0

3 years ago

I really need help!!! I will give more points to people that actually help!

Andru [333]

Answer:

C8H18 2 114.22852

O2 25 31.9988

CO2 16 44.0095

H2O 18 18.01528

Explanation:

6 0

3 years ago

500 mL of water is added to 400 mL of 0.35 M HCl. Find the concentration of the diluted solution.

jarptica [38.1K]

The concentration of diluted solution is 0.16 M

<u>Explanation:</u>

As, the number of moles of diluted solution and concentrated solution will be same.

So, the equation used to calculate concentration will be:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated HCl solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted HCl solution

We are given:

$M_1=0.35M\\V_1=400mL\\M_2=?M\\V_2=(500+400)mL=900mL$

Putting values in above equation, we get:

$0.35\times 400=M_2\times 900\\\\M_2=\frac{0.35\times 400}{900}=0.16M$

Hence, the concentration of diluted solution is 0.16 M

5 0

3 years ago