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Nastasia [14]
3 years ago
8

Steel is an alloy consisting of Fe with a small amount of C. Elemental Cr can be added to steel to make the steel less likely to

rust
a. True
b. False
Chemistry
1 answer:
Yakvenalex [24]3 years ago
8 0
The statement is true
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MARK THE EXTENSIVE PROPERTIES(Check that all apply)
Anarel [89]
I think its just Mass
5 0
3 years ago
Given the following reaction:
Semenov [28]

Answer:

The answer to your question is 0.35 moles of ZnCl₂

Explanation:

Data

moles of ZnCl₂ = ?

mass of Zn = 23 g

mass of CuCl₂ = excess

Balanced chemical reaction

             Zn + CuCl₂   ⇒   ZnCl₂  +  Cu

Process

1.- Convert the mass of Zn to moles

-Look for the atomic mass of Zn

Atomic mass = 65.4 g

-Convert the grams to moles

            65.4 g -------------- 1 mol

             23 g  ----------------  x

               x = (23 x 1)/65.4

               x = 23 / 65.4

               x = 0.35 moles of Zn

2.- Calculate the moles of ZnCl₂ using proportions and cross multiplication, and the coefficients of the balanced chemical reaction.

              1 mol of Zn ---------------- 1 mol of ZnCl₂

             0.35 moles of Zn --------  x

              x = (0.35 x 1) / 1

              x = 0.35 moles of ZnCl₂

7 0
3 years ago
Which of the following is a INCORRECT ionic compound formula? <br> MgO<br> Na20<br> MgCl<br> NaCl
hoa [83]

Answer:

Na2O

explanation.

Ionic bonds refers to complete transfer of electrons from one atom to another

3 0
3 years ago
AP CHEM answer and i will give brainliest, image attached
scoundrel [369]

Answer:

what is this i dont know what kind of math this is

6 0
1 year ago
How many lead (Pb) atoms are in a 5.32 g sample of pure lead?
Elanso [62]

Answer:

1.55×10²² molecules.

Explanation:

We'll begin by calculating the number of mole in 5.32 g of pure lead (Pb). This can be obtained as follow:

Mass of Pb = 5.32 g

Molar mass of Pb = 207 g/mol

Mole of Pb =?

Mole = mass /molar mass

Mole of Pb = 5.32/207

Mole of Pb = 0.0257 mole

Finally, we shall determine the number of molecules in 0.0257 mole of Pb. This can be obtained as follow:

From Avogadro's hypothesis,

I mole of Pb contains 6.02×10²³ molecules.

Therefore, 0.0257 mole will contain = 0.0257 × 6.02×10²³ = 1.55×10²² molecules.

Therefore, 5.32 g of pure lead (Pb) contains 1.55×10²² molecules.

4 0
3 years ago
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