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Firdavs [7]
3 years ago
8

Which answer describes the pattern in this sequence? −7, −11, −15, −19, ...

Mathematics
1 answer:
Gekata [30.6K]3 years ago
3 0
The answer is option 2, it subtracts by four each time.
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2x + 4y = 12 y = x – 3 What is the solution to the system of equations? (–1, 8) (8, –1) 5 1/2 1/2 5
Goryan [66]

Answer:

The solution is (8, -1).

Step-by-step explanation:

2x + 4y = 12..........(1)

y = 1/4x – 3 ..........(2)

Substitute y = x - 3 in equation (1):

2x + 4(1/4x - 3) = 12

2x + x - 12 = 12

3x = 24

x = 8.

Now substitute for x in equation (2):

y = 1/4 *8 - 3

y = -1.

5 0
3 years ago
Which of the following obtains data from a subset of a population to evaluate traits of the population?
andrey2020 [161]
Is A across sectial survey
4 0
3 years ago
Linda sells the bracelets and necklaces she makes online. She sells her bracelets for $6 and her necklaces for $10.
Sholpan [36]

Answer:

She get $16 dollars

Step-by-step explanation:

4 0
2 years ago
Clark and Lana take a 30-year home mortgage of $128,000 at 7.8%, compounded monthly. They make their regular monthly payments fo
svp [43]

Answer:

Step-by-step explanation:

From the given information:

The present value of the house = 128000

interest rate compounded monthly r = 7.8% = 0.078

number of months in a year n= 12

duration of time t = 30 years

To find their regular monthly payment, we have:

PV = P \begin {bmatrix}  \dfrac{1 - (1 + \dfrac{r}{n})^{-nt}}{\dfrac{r}{n}}    \end {bmatrix}

128000 = P \begin {bmatrix}  \dfrac{1 - (1 + \dfrac{0.078}{12})^{- 12*30}}{\dfrac{0.078}{12}}    \end {bmatrix}

128000 = 138.914 P

P = 128000/138.914

P = $921.433

∴ Their regular monthly payment P = $921.433

To find the unpaid balance when they begin paying the $1400.

when they begin the payment ,

t = 30 year - 5years

t= 25 years

PV= 921.433 \begin {bmatrix}  \dfrac{1 - (1 - \dfrac{0.078}{12})^{25*30}}{\dfrac{0.078}{12}}    \end {bmatrix}

PV = $121718.2714

C) In order to estimate how many payments of $1400  it will take to pay off the loan, we have:

121718.2714 =  \begin {bmatrix}  \dfrac{1300  (1 - \dfrac{12.078}{12}))^{-nt}}{\dfrac{0.078}{12}}    \end {bmatrix}

121718.2714 = 200000  \begin {bmatrix}  (1 - \dfrac{12.078}{12}))^{-nt}   \end {bmatrix}

\dfrac{121718.2714}{200000 } =  \begin {bmatrix}  (1 - \dfrac{12.078}{12}))^{-nt}   \end {bmatrix}

0.60859 =  \begin {bmatrix}  (1 - \dfrac{12}{12.078}))^{nt}   \end {bmatrix}

0.60859 = (0.006458)^{nt}

nt = \dfrac{0.60859}{0.006458}

nt = 94.238 payments is required to pay off the loan.

How much interest will they save by paying the loan using the number of payments from part (c)?

The total amount of interest payed on $921.433 = 921.433 × 30(12) years

= 331715.88

The total amount paid using 921.433 and 1300 = (921.433 × 60 )+( 1300 + 94.238)

= 177795.38

The amount of interest saved = 331715.88  - 177795.38

The amount of interest saved = $153920.5

6 0
3 years ago
Help me solve this pleaseeee
MaRussiya [10]

Answer:

f(n) = 6n + 12

Step-by-step explanation:

There is a common difference in consecutive number of seats, that is

42 - 36 = 36 - 30 = 30 - 24 = 24 - 18 = 6

This indicates the sequence is arithmetic with nth term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 18 and d = 6 , then

f(n) = 18 + 6(n - 1) = 18 + 6n - 6 = 6n + 12

5 0
3 years ago
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