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miv72 [106K]
4 years ago
10

How many electrons does it take to fill the outer energy level of most atoms

Chemistry
1 answer:
Orlov [11]4 years ago
5 0
Depends on the element it can by up to 3, 8, or maybe 16.
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Justify the statement, "nuclear energy is harmful as well as useful."​
Olenka [21]

Nuclear energy is harmful because it releases of harmful ionizing radiation and has been employed in the production of atomic bombs and hydrogen bombs.

Nuclear energy is beneficial in that it produces vast amount of energy for domestic and industrial purposes.

<h3>What is nuclear energy?</h3>

Nuclear energy refers to the energy which is produced as a result of the changes that occur in the nucleus of atoms of elements.

Nuclear energy produces the largest amount of energy when compared to other forms of energy sources.

Nuclear energy is produced by two types of nuclear reactions:

  • Nuclear fission and Nuclear fusion

Nuclear energy is harmful in that it results in the release of harmful ionizing radiation which damages cells and tissues of living organisms.

Nuclear energy is also harmful because nuclear energy has been employed in the production of atomic bombs and hydrogen bombs.

On the other hand, nuclear energy is beneficial in that it produces vast amount of energy which can be used for domestic and industrial purposes. It also produces fewer wastes that damage the environment compared to fossil fuels.

In conclusion, nuclear energy is both beneficial and harmful.

Learn more about nuclear energy at: brainly.com/question/15214614

#SPJ1

8 0
2 years ago
The decomposition of \rm XY is second order in \rm XY and has a rate constant of6.96Ã10â3M^{-1} \cdot s^{-1} at a certain temper
LUCKY_DIMON [66]

Explanation:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

Half life for second order kinetics is given by:

t_{1/2}=\frac{1}{k\times a_0}

k = rate constant =?

a_0 = initial concentration

a = concentration left after time t

Integrated rate law for second order kinetics is given by:

\frac{1}{a}=kt+\frac{1}{a_0}

a) Initial concentration of XY = a_o=0.100 M

Rate constant of the reaction = k = 6.96\times 10^{-3} M^{-1} s^{-1}

Half life of the reaction is:

t_{1/2}=\frac{1}{6.96\times 10^{-3} M^{-1} s^{-1}\times 0.100 M}

=1,436.78 s

1,436.78 seconds is the half-life for this reaction.

b) Initial concentration of XY = 0.100 M

Final concentration after time t = 12.5% of 0.100 M = 0.0125 M

\frac{1}{0.0125 M}=6.96\times 10^{-3} M^{-1} s^{-1}\times t+\frac{1}{0.100M}

Solving for t;

t = 10,057.47 seconds

In 10,057.47 seconds the concentration of XY will become 12.5% of its initial concentration.

c) Initial concentration of XY = 0.200 M

Final concentration after time t = 12.5% of 0.200 M = 0.025 M

\frac{1}{0.025 M}=6.96\times 10^{-3} M^{-1} s^{-1}\times t+\frac{1}{0.200M}

Solving for t;

t = 5,028.73 seconds

In 5,028.73 seconds the concentration of XY will become 12.5% of its initial concentration.

d) Initial concentration of XY = 0.160 M

Final concentration after time t = 6.20\times 10^{-2} M

\frac{1}{6.20\times 10^{-2} M}=6.96\times 10^{-3} M^{-1} s^{-1}\times t+\frac{1}{0.200M}

Solving for t;

t = 1,419.40 seconds

In 1,419.40 seconds the concentration of XY will become 6.20\times 10^{-2} M.

e)  Initial concentration of SO_2Cl_2= 0.050 M

Final concentration after time t = x

t = 55.0 s

\frac{1}{x}=6.96\times 10^{-3} M^{-1} s^{-1}\times 55.0 s+\frac{1}{0.050 M}

Solving for x;

x = 0.04906 M

The concentration after 55.0 seconds is 0.04906 M.

f) Initial concentration of XY= 0.050 M

Final concentration after time t = x

t = 500 s

\frac{1}{x}=6.96\times 10^{-3} M^{-1} s^{-1}\times 500 s+\frac{1}{0.050 M}

Solving for x;

x = 0.04259 M

The concentration after 500 seconds is 0.0.04259 M.

7 0
3 years ago
If 20 grams of aluminum react with 200 grams of bromide to form aluminum bromide and no aluminum is left after the reaction, but
Varvara68 [4.7K]
The answer is: 197 grams

Why?

All 20 grams of aluminum was used to form aluminum bromide. Only 177 grams of bromide were used to make aluminum bromide, since 23 grams were left over.

20 grams + 177 grams = 197 grams, so the answer is 197 grams.
8 0
4 years ago
Which of the following has nonvolatile bonds
lord [1]

Answer:

I can provide a proper answer since there are no bonds specified.

Explanation:

8 0
3 years ago
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A 63 kg object needs to be lifted 7 meters in a matter of 5 seconds. Approximately how much horsepower is required to achieve th
Digiron [165]
A. is the correct answer!
7 0
3 years ago
Read 2 more answers
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