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miv72 [106K]
3 years ago
10

How many electrons does it take to fill the outer energy level of most atoms

Chemistry
1 answer:
Orlov [11]3 years ago
5 0
Depends on the element it can by up to 3, 8, or maybe 16.
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How many molecules are contained in 125 grams of water, H20?
sergejj [24]
Answer:

18,01528

Explanation:
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2 years ago
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What is a substance and what are the two types of substances?
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A pure substance has a constant composition and cannot be separated into simpler substances by physical means. There are two types of pure substances: elements and compounds. Elements: are pure substances made up of only l type of atom. Atoms of the same element are identical in properties.
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3 years ago
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3.604m + 104.29m + 3.1m + 17.41m. The sum expressed in the correct number of significant figures is
dedylja [7]

Answer:

128.4 m

Explanation:

3.604m + 104.29m + 3.1m + 17.41m

Add all the values

= 128.404 m

The significant figure rule for addition is for the sum to have the same number of decimal places as the value with the least number of decimal places. In the addition sentence 3.604m + 104.29m + 3.1m + 17.41m, the value with the least number of decimal places is 3.1, which has 1 decimal place. Therefore, we round our sum so that it also has 1 decimal place.

128.404 m

= 128.4 m

I hope this helps!

7 0
2 years ago
When methane ( CH4 ) burns, it reacts with oxygen gas to produce carbon dioxide and water. The unbalanced equation for this reac
slega [8]
<h2>Answer:</h2>1.33*10^{-2}grams

<h2>Explanations</h2>

The complete balanced equation for the given reaction is expressed as;

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)

Given the following parameters

Mass of CH4 = 5.90×10^−3 g = 0.0059grams

Determine the moles of methane

\begin{gathered} moles\text{ of CH}_4=\frac{mass}{molar\text{ mass}} \\ moles\text{ of CH}_4=\frac{0.0059}{16.04} \\ moles\text{ of CH}_4=0.000368moles \end{gathered}

According to stoichimetry, 1 mole of methane produces 2 moles of water, hence the moles of water required will be:

\begin{gathered} moles\text{ of H}_2O=\frac{2}{1}\times0.000368 \\ moles\text{ of H}_2O=0.000736moles \end{gathered}

Determine the mass of water produced

\begin{gathered} Mass\text{ of H}_2O=moles\times molar\text{ mass} \\ Mass\text{ of H}_2O=0.000736\times18.02 \\ Mass\text{ of H}_2O=0.0133grams=1.33\times10^{-2}grams \end{gathered}

Therefore the mass of water produced from the complete combustion of 5.90×10−3 g of methane is 1.33 * 10^-2grams

5 0
1 year ago
Which statement describes a problem with the peer review process in scientific research?
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Its A.It can sometimes reject important new ideas or novel techniques.<span>
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6 0
3 years ago
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