The element strontium (atomic number = 38) has four naturally-occurring isotopes. They are: Isotope / Percent Abundance / Mass (amu) Sr-84 / 0.56% / 83.9134 Sr-86 / 9.86% / 85.9093 Sr-87 / 7.00% / 86.9089 Sr-88 / 82.58% / 87.9056 The first thing to do is to convert all of the percentages to decimal fractions. To do that just move the decimal point two places to the left. Be careful, though...if the decimal is already at the front of the number you STILL have to move it two places. Add leading zeroes as necessary. 0.56% becomes 0.0056 9.86% becomes 0.0986 7.00% becomes 0.0700 82.58% becomes 0.8258 Next multiply each of the decimal fractions by the mass of each isotope. 0.0056 x 83.9134 = 0.47 0.0986 x 85.9093 = 8.47 0.0700 x 86.9089 = 6.08 0.8258 x 87.9056 = 72.59 Finally add the results to find the average atomic mass. 0.47 + 8.47 + 6.08 + 72.59 = 87.61 amu This agrees closely with the listed atomic mass for strontium, so I know I probably did my work correctly. I hope that helps
Answer:
Explanation:
so we have to solve it or just answer it?
Answer:

Explanation:
Hello,
In this case, since in a dilution process the moles of the solute must remain unchanged, we use the volumes and molarities as shown below:

Clearly, the concentrated solution is 7.00M and the diluted solution is unknown, thus, the concentration of the diluted solution after the dilution to 100 mL is:

Best regards.
Answer:
<em>OILS</em>
Explanation:
Oils are viscous liquids at room temperature, with high carbon and hydrogen content. Vegetable oils in this case are triglycerides extracted from plants seeds or fruit.
So we'd have olive oils, canola oils and corn oils.
I hope this explanation is clear and simple.
Answer:
H2 (g) + I2 (g) = 2HI (g)
Explanation:
Forward reaction:H2(g)+I2(g)→2HI(g)
Reverse reaction:2HI(g)→H2(g)+I2(g)