--> 0.058 g NaCl = 100 g solution
<span>1 g = 100/0.058 g solution </span>
<span>1.5 g = 150/0.058 g = 2586 g solution </span>
<u>Answer:</u> The average rate of disappearance of A is
<u>Explanation:</u>
The given chemical reaction follows:
The average rate of the reaction for disappearance of A is given as:
Or,
where,
= final concentration of A = 0.11 M
= initial concentration of A = 0.91 M
= final time = 90 minutes
= initial time = 0 minutes
Putting values in above equation, we get:
Hence, the average rate of disappearance of A is
In order to find the number of moles in a sample we are tasked with first finding the number of moles in that sample. This is because the moles in a substance indicates the amount of the substance that contains the same number of particles as 12 g of the Carbon-12 isotope [or equivalent to 6.02 × 10²³ (which is used as a standard in the world of moles).
Now,
If moles = mass ÷ molar mass
then mol of aluminum = 100 g ÷ 27g/mol
= 3.704 mol
Now that you have calculated the moles then you can do a simple ratio and multiplication at arrive at the number of atoms that would be present in the 100 g of aluminum.
if 1 mol of aluminum contains 6.02 × 10²³ atoms
then let 3.704 mol of aluminum contain x
∴ x = 3.704 mol × (6.02 × 10²³)
= 2.23 × 10²⁴
∴ 100 g of Al would contain ~ 2.23 × 10²⁴ atoms
Br- + 2MnO4- + 2H+ → BrO3- + 2MnO2 + H2O
<h3>Further explanation</h3>
Given
MnO4- + Br- = MnO2 + BrO3-
Required
The half-reaction
Solution
In acidic conditions :
1. Add the coefficient
2. Equalization O atoms (add H₂O) on the O-deficient side.
3. Equalization H atoms (add H⁺ ) on the H -deficient side. .
4. Equalization of charge (add electrons (e) )
5. Equalizing the number of electrons and then adding the two half -reactions together
Oxidation : Br- → BrO3-
Reduction : MnO4- → MnO2
Br- + 3H2O → BrO3-
MnO4- → MnO2 + 2H2O
Br- + 3H2O → BrO3- + 6H+
MnO4- + 4H+ → MnO2 + 2H2O
Br- + 3H2O → BrO3- + 6H+ + 6e- x1
MnO4- + 4H+ + 3e- → MnO2 + 2H2O x2
- Equalizing the number of electrons and then adding the two half -reactions together
Br- + 3H2O → BrO3- + 6H+ + 6e-
2MnO4- + 8H+ + 6e- → 2MnO2 + 4H2O
Br- + 2MnO4- + 3H2O + 8H+ + 6e- → BrO3- + 2MnO2 + 6H+ + 4H2O + 6e-
Br- + 2MnO4- + 2H+ → BrO3- + 2MnO2 + H2O
<span>Alpha decay or α-decay is a type of radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and thereby transforms or 'decays' into an atom with a mass number that is reduced by four and an atomic number that is reduced by two.
You didn't list any options, but I hope this helps!
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