1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zysi [14]
3 years ago
8

Is this true or false? :D

Chemistry
2 answers:
Vladimir [108]3 years ago
7 0

the ans. is false (:) ok

Valentin [98]3 years ago
6 0

Answer:

true i am pretty sure

Explanation:

You might be interested in
When an unknown amine reacts with an unknown acid chloride, an amide with a molecular mass of 163 g/mol (M = 163 m/z) is formed.
DanielleElmas [232]

Answer:

            As the molecular mass of given amine is 163 g/mol (a odd number) it means that this compound contains a odd number of Nitrogen atoms. We will first apply Rule of Thirteen to get the molecular formula.

Rule of Thirteen:

First divide the parent peak value by 13 as,

                = 163 ÷ 13

                = 12.53

Now, multiply 13 by 12,

                = 13 × 12 (here, 12 specifies number of carbon atoms)

                = 156

Now subtract 156 from 163,

                = 163 - 156

                = 7

Add 7 into 12,

                = 7 + 12

                = 19 (hydrogen atoms)

So, the rough formula we have is,

                                                       C₁₂H₁₉

Now, add one Nitrogen atom to above formula and subtract one Carbon and 2 Hydrogen atoms as these numbers are equal to atomic mass of Nitrogen atom as,

                C₁₂H₁₉   -------N-------->    C₁₁H₁₇N

Also, as shown in ¹³C-NMR there is one peak around 180 ppm and the peak at 1661 cm⁻¹ in IR spectrum is characteristic to carbonyl group hence, we will add one oxygen atom to the chemical formula accordingly. i.e.

                C₁₁H₁₇N   -------O-------->    C₁₀H₁₃NO

Molecular Formula: C₁₀H₁₃NO

Also,

In NMR the the four peaks around 120 ppm are assigned to a mono substituted benzene ring.

The absence of IR peak above 3200 cm⁻³ also confirms that the amine is tertiary in nature and there is no hydrogen attached to the nitrogen atom.

It can be observed that the peaks in upfield are duplicating. This can be due to the presence of rotamers of said compound.

The most plausible structure for given data is shown below, and the resonance structure along with rotamers are also shown.

6 0
3 years ago
What can be absorbed or produced as the result of a chemical reaction???
tia_tia [17]
Heat can be absorbed or produced
6 0
3 years ago
6. Why does the sun seem to change position in the sky?
Dafna11 [192]
A. Earth’s Rotation
4 0
3 years ago
Explain whether your breakfast was a compound, homogeneous mixture, or heterogenous mixture.
leonid [27]


what did you eat for breakfast?

I can't help you otherwise

7 0
3 years ago
Please help quickly as possible thank you :) ​
WARRIOR [948]

Answer:

moving object transfers some to the stationary object causing it to move a it. remember that momentum is always conserved though - it is the same at the start before the event and after it.

Explanation:

4 0
3 years ago
Other questions:
  • What are atoms made of
    8·2 answers
  • What metric measurement is similar to a mile?
    10·2 answers
  • Which mathematical statement correctly relates qsys and qsurr? A. qsys = qsurr B. qsys < qsurr C. qsys > –qsurr D. qsys =
    6·1 answer
  • What is the empirical formula for P4O10?
    14·2 answers
  • ¿Qué sucede cuando dos sustancias se juntan?
    13·1 answer
  • Malik analyzed three samples to test which element was a metalloid. The table shows his results. A 7-column table with 3 rows. T
    14·2 answers
  • The lifting force on an airplane's wing does which of the following?
    10·2 answers
  • Please help ASAPPPPPPPPPPPPPPP
    8·1 answer
  • Which type of rock does B represent?
    15·1 answer
  • Ordinary water boils at 100°C. Can it be made to boil at 95°C or 105°C.​
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!