How many moles of an ideal gas would occupy a 400.0 liter container when the temperature is 300.0 K and the pressure is 2.20 atm
1 answer:
You might be interested in
Answer:
The vapor pressure at temperature 363 K is 0.6970 atm
The vapor pressure at 383 K is 1.410 atm
Explanation:
To calculate of the reaction, we use clausius claypron equation, which is:
where,
= vapor pressure at temperature
= vapor pressure at temperature
= Enthalpy of vaporization
R = Gas constant = 8.314 J/mol K
1)
= initial temperature =363 K
= final temperature =373 K
Putting values in above equation, we get:
The vapor pressure at temperature 363 K is 0.6970 atm
2)
= initial temperature =373 K
= final temperature =383 K
Putting values in above equation, we get:
The vapor pressure at 383 K is 1.410 atm