(1) The image of an object placed further from the lens than the focal point will be upside down and smaller than the object.
(2) When light rays reflect, they bounce back.
(3) Images formed by a concave lens will look magnified.
(4) When light rays enter a different medium, they bend.
<h3>
1.0 Object placed further from the lens than the focal point</h3>
The image of an object placed further from the lens than the focal point will be diminished and inverted.
Thus, the correct answer will be "upside down and smaller than the object".
<h3>2.0 What is reflection of light?</h3>
The ability of light to bounce back when it strike a hard surface is known as refection.
<h3>3.0 Image formed by concave lens</h3>
A concave lens is diverging lens is usually virtual, erect and magnified.
<h3>4.0 Refraction of light</h3>
The change in speed of light when it travels from medium to another medium is known as refraction. Refraction is also, the ability of light to bend around obstacles.
Learn more about reflection and refraction of light here: brainly.com/question/1191238
I would say 3 is the answer
Answer:
1 cm ± 0.05 cm
Explanation:
A ruler is readable to ±0.05 cm. This implies that any measurement taken using the ruler could be uncertain by 0.05 cm above or below the true value.
Hence, ±0.05 cm is called the uncertainty or the precision of the ruler.
We obtained this from the fact that the meter rule is graduated in units of centimetres (cm). This implies that the smallest scale division is 1 mm. Thus, the uncertainty of the meter rule is given by; Δx = smallest increment/2 = 1mm/2 = 0.5mm = 0.05cm.
Answer: *360 mph*
Explanation:
I am pretty sure that it is 360 mph
3 times 120 = 360
Answer : distance, d = 463.7 m
Explanation :
According to the given condition it can be assumed that the first echo would be heard from closest cliff. The second echo is from farther cliff and the third echo is from the reflection between the two cliffs.
Let the distance between the first cliff and the point of firing is x and y is the distance between the second cliff and the point of firing.
Then the first echo will travel 2x distance, second will travel 2y distance and third will travel 2x +2y.
So, using above data :
and
On solving :
x = 321.9 m and y = 141.8 m
Hence, total distance between two cliffs is d = 321.9 m + 141.8 m = 463.7 m