Ask question

Ask question

All categories

3 years ago

5

Assuming the radius of diatomic molecules is approximately 2.3 ×10-10 m for what pressure in Pa will the mean free path in room-

temperature (20°C) nitrogen be 0.027 m? The Boltzmann constant is 1.38 × 10-23 J/K, Avogadro’s number is 6.02 × 1023 molecules/mole, and the ideal gas constant is R = 8.315 J/mol•K = 0.0821 L ∙ atm/mol ∙ K.

1 answer:

shutvik [7]3 years ago

8 0

For a radius of diatomic molecules is approximately 2.3 ×10-10 m, the pressure in Pa is mathematically given as

P=0.134Pa

<h3>What pressure in Pa will the mean free path in room-temperature (20°C) nitrogen be 0.027 m?</h3>

Generally, the equation for the ideal gas is mathematically given as

PV=nRT

Therefore

$P=\frac{1kT}{\sqrt{2}\pi(p)d^2}$

$P=\frac{1.38*10^-23*293}{\sqrt{2}\pi*(2*1.3*10^{-10})^2)*0.1}$

P=0.134Pa

In conclusion, Pressure

P=0.134Pa

Read more about Pressure

brainly.com/question/25688500

You might be interested in

Science If you want to find the energy quantum of light, you multiply the frequency of the radiation (v) by "h". What is "h"?

weqwewe [10]

Answer:

"h" signifies Planck's constant

Explanation:

In the equation energy E = h X v

The "h" there signifies Planck's constant

Planck's constant is a value, that shows the rate at which the energy of a photon increases/decreases, as the frequency of its electromagnetic wave changes.

It was named after Max Planck who discovered this unique relationship between the energy of a light wave and its frequency.

Planck's constant, "h" is usually expressed in Joules second

Planck's constant = $6.62607015 \times 10^{-34} J.s$

7 0

3 years ago

10m= (5.0) + (.5)(9.8)(5.0)

Norma-Jean [14]

M=2.45 because you multiply out the equation on the right and divide by 10

8 0

4 years ago

What is the average speed of a car that travels 60 meters in 2<br> seconds?

blondinia [14]

Answer:

30 m/s

Explanation:

Speed is distance over time. 60 meters / 2 seconds, = 30 m/s.

6 0

3 years ago

John took 0.75 hours to bicycle to his grandmother's house, a distance of 4 km. What is his velocity?

ddd [48]

Answer:

5.3Km/hr

Explanation:

Velocity=Displacement/Time

D=4km;T=0.75hr

V=4/0.75=5.33..

6 0

3 years ago

A trick shot archer shoots an arrow with a velocity of 30.0 m/s at an angle of 20.0 degrees with respect to the horizontal. An a

svlad2 [7]

Answer:

$u'=10.259\ m.s^{-1}$ is the initial velocity of tossing the apple.

the apple should be tossed after $\Delta t=0.0173\ s$

Explanation:

Given:

velocity of arrow in projectile, $v=30\ m.s^{-1}$

angle of projectile from the horizontal, $\theta=20^{\circ}$

distance of the point of tossing up of an apple, $d=30\ m$

<u>Now the horizontal component of velocity:</u>

$v_x=v\ cos\ \theta$

$v_x=30\times cos\ 20^{\circ}$

$v_x=28.191\ m.s^{-1}$

<u>The vertical component of the velocity:</u>

$v_y=v.sin\ \theta$

$v_y=30\times sin\ 20^{\circ}$

$v_y=10.261\ m.s^{-1}$

<u>Time taken by the projectile to travel the distance of 30 m:</u>

$t=\frac{d}{v_x}$

$t=\frac{30}{28.191}$

$t=1.0642\ s$

<u>Vertical position of the projectile at this time:</u>

$h=v_y.t-\frac{1}{2}g.t^2$

$h=10.261\times 1.0642-\frac{1}{2} \times 9.8\times 1.0642^2$

$h=5.3701\ m$

<u>Now this height should be the maximum height of the tossed apple where its velocity becomes zero.</u>

$v'^2=u'^2-2g.h$

$0^2=u'^2-2\times 9.8\times 5.3701$

$u'=10.259\ m.s^{-1}$ is the initial velocity of tossing the apple.

<u>Time taken to reach this height:</u>

$v'=u'-g.t'$

$0=10.259-9.8\times t'$

$t'=1.0469\ s$

<u>We observe that </u> $t>t'$ <u> hence the time after the launch of the projectile after which the apple should be tossed is:</u>

$\Delta t=t-t'$

$\Delta t=1.0642-1.0469$

$\Delta t=0.0173\ s$

8 0

3 years ago