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Fed [463]
3 years ago
10

Number the pictures in order of length from 1. to 6. The shortest pictures should have the number 1.

Mathematics
2 answers:
lakkis [162]3 years ago
8 0
First picture-5
Second picture-2
Third picture-1
Fourth picture-3
Firth picture-4
Sixth picture-6
Llana [10]3 years ago
5 0

Answer:

5, 2, 1, 3, 4, 6.

Step-by-step explanation:

Measure each feather in centimeters. Then order them from least to greatest.

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The table below shows the coordinates of a figure that was transformed. Which is a correct description of the transformation?
Hitman42 [59]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
Solve the equation. Round to the nearest hundredth. Show work.
Burka [1]

Answer:

x=-0.75

Step-by-step explanation:

The given equation is

4^{-5x-7}=6^{2x-1}

We take logarithm of both sides to base 10.

\log(4^{-5x-7})=\log(6^{2x-1})

(-5x-7)\log(4)=(2x-1)\log(6)

We expand the brackets to get;

-5x\log(4)-7\log(4)=2x\log(6)-\log(6)

Group similar terms;

-7\log(4)+\log(6)=2x\log(6)+5x\log(4)

-7\log(4)+\log(6)=(2\log(6)+5\log(4))x

\frac{-7\log(4)+\log(6)}{(2\log(6)+5\log(4))}=x

x=-0.752478

To the nearest hundredth.

x=-0.75

3 0
3 years ago
How does supply and demand affect consumers?
mezya [45]
Supply and demand affects prices which affects consumers want and likelihood of buying a product
5 0
2 years ago
Suppose 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. Use a 0.05 significance
lana66690 [7]

Answer:

Null Hypothesis, H_0 : p = 0.20  

Alternate Hypothesis, H_a : p > 0.20  

Step-by-step explanation:

We are given that 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea.

We have to use a 0.05 significance level to test the claim that more than 20​% of users develop nausea.

<em>Let p = population proportion of users who develop nausea</em>

So, <u>Null Hypothesis,</u> H_0 : p = 0.20  

<u>Alternate Hypothesis</u>, H_a : p > 0.20  

Here, <u><em>null hypothesis</em></u> states that 20​% of users develop nausea.

And <u><em>alternate hypothesis</em></u> states that more than 20​% of users develop nausea.

The test statistics that would be used here is <u>One-sample z proportion</u> test statistics.

                     T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }   ~ N(0,1)

where,  \hat p = proportion of users who develop nausea in a sample of 241 subjects =  \frac{54}{241}  

             n = sample of subjects = 241

So, the above hypothesis would be appropriate to conduct the test.

6 0
3 years ago
Subtract the following polynomials.<br><br> (5x2+6)−(6x−5x2)<br><br> im bad at math ;-;
Eddi Din [679]

Answer:

First off if you want this answered make sure it's clear when your multiplying or using X

5 0
3 years ago
Read 2 more answers
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