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An electron in a TV picture tube is accelerated through a potential difference of 10 kV before it hits the screen. What is the k
1 answer:
Answer:
10,000 eV
Explanation:
According to the law of conservation of energy, the kinetic energy gained by the electron is equal to its change in electric potential energy:
where:
K is the kinetic energy of the electron
is the magnitude of the charge of the electron
is the potential difference through which the electron has been accelerated
For this electron in the TV, we have
Therefore, the kinetic energy of the electron in electronvolts is
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Answer:
Explanation:
Assuming this problem: "Part (a) of the figure attached shows a non-conducting rod with a uniformly distributed charge +Q. The rod forms a half circle with radius R and produces an electric field of magnitude Earc at its center of curvature P. If the arc is collapsed to a point at distance R from P (Figure b), by what factor is the magnitude of the electric field at P multiplied?"
On this case the charge density is given by this formula:
assuming a half circle
We can find the force acting on the x axis with this:
We can cnvert the integral using the symmetrical property:
And we can find the electric field like this:
And the electric field just by the charge is given by:
And if we find the ratio for the two electrical fields we got:
