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kotegsom [21]
4 years ago
8

An electron in a TV picture tube is accelerated through a potential difference of 10 kV before it hits the screen. What is the k

inetic energy of the electron in electron volts?(1 eV = 1.6 ? 10 -19 J)
Physics
1 answer:
laiz [17]3 years ago
7 0

Answer:

10,000 eV

Explanation:

According to the law of conservation of energy, the kinetic energy gained by the electron is equal to its change in electric potential energy:

K=\Delta U=q \Delta V

where:

K is the kinetic energy of the electron

q=1 e is the magnitude of the charge of the electron

\Delta V is the potential difference through which the electron has been accelerated

For this electron in the TV, we have

\Delta V=10 kV=10000 V

Therefore, the kinetic energy of the electron in electronvolts is

K=(1 e)(10000 V)=10000 eV

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The rod forms a 10/22 of circle with radius R and produces an electric field of magnitude Earc at its center of curvature P.
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Answer:

\frac{E_q}{E_a}=\frac{\pi}{2}

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Assuming this problem: "Part (a) of the figure attached shows a non-conducting rod with a uniformly distributed charge +Q. The rod forms a half circle with radius R and produces an electric field of magnitude Earc at its center of curvature P. If the arc is collapsed to a point at distance R from P (Figure b), by what factor is the magnitude of the electric field at P multiplied?"

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We can find the force acting on the x axis with this:

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We can cnvert the integral using the symmetrical property:

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<span>"In designing electrical circuits, it is important to know the characteristics of circuits in order to know how to solve related problems that will arise whenever there will be problems in the circuits made. For example, series circuits makes the other lights go off whenever one bulb does not work. It would be easier to determine how to fix it because we know what type of circuit it is."
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