<h2>
The balloon is moving when it is halfway down the building at 20.78 m/s.</h2>
Explanation:
We have equation of motion v² = u² + 2as
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Displacement, s = 0.5 x 44 = 22 m
Substituting
v² = u² + 2as
v² = 0² + 2 x 9.81 x 22
v² = 431.64
v = 20.78 m/s
Velocity at 22 m = 20.78 m/s
The balloon is moving when it is halfway down the building at 20.78 m/s.
Answer:
Weight on Earth = We = 186.2 N
Weight on Mars = Wm = 70.94 N
Explanation:
The weight of an object is defined as the force applied on the object by the gravitational field. The magnitude of weight is given by the following formula:
W = mg
were,
W= Weight of Eric
m = mass of Eric
g = acceleration due to gravity
ON EARTH:
W = We = Eric's Weight on Earth = ?
m = Eric's Mass on Earth = 19 kg
ge = acceleration due to gravity on Earth = 9.8 m/s²
Therefore,
We = (19 kg)(9.8 m/s²)
<u>We = 186.2 N</u>
<u></u>
ON MARS:
W = Wm = Eric's Weight on Mars = ?
m = Eric's Mass on Mars = 19 kg
gm = acceleration due to gravity on Mars = 0.381(ge) = (0.381)9.8 m/s² = 3.733 m/s²
Therefore,
Wm = (19 kg)(3.733 m/s²)
<u>Wm = 70.94 N</u>
Answer:
Explanation:
Using Kepler's third law, we can relate the orbital periods of the planets and their average distances from the Sun, as follows:
Where 
and 
are the orbital periods of Mercury and Earth respectively. We have 
and 
. Replacing this and solving for
