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vodka [1.7K]
3 years ago
8

The speed of an object undergoing constant acceleration increased from 8.0 meters per second to 16.0 meters per second in 10. Se

conds . How far does the object travel during the 10. Seconds
Physics
1 answer:
saw5 [17]3 years ago
6 0

v₀ = initial speed of the object = 8 meter/second

v = final speed of the object = 16 meter/second

t = time taken to increase the speed = 10 seconds

d = distance traveled by the object in the given time duration = ?

using the kinematics equation

d = (v + v₀) t/2

inserting the above values in the above equation

d = (16 + 8) (10)/2

d = 120 meter


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Serhud [2]

Answer:

Δv = 12 m/s, but we are not given the direction, so there are really an infinite number of potential solutions.

Maximum initial speed is 40.6 m/s

Minimum initial speed is 16.6 m/s

Explanation:

Assume this is a NET impulse so we can ignore friction.

An impulse results in a change of momentum

The impulse applied was

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If the impulse was applied in the direction the car was already moving, the initial velocity was

vi = 28.6 - 12 = 16.6 m/s

if the impulse was applied in the direction opposite of the original velocity, the initial velocity was

vi = 28.6 + 12 = 40.6 m/s

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5 0
3 years ago
A circular loop of flexible iron wire has an initial circumference of 165cm , but its circumference is decreasing at a constant
ArbitrLikvidat [17]

Answer:

emf induced is 0.005445 V and direction is clockwise because we can see area is decrease and so that flux also decrease so using right hand rule direction of current here clockwise

Explanation:

Given data

initial circumference = 165 cm

rate = 12.0 cm/s

magnitude = 0.500 T

tome = 9 sec

to find out

emf induced and direction

solution

we know emf in loop is - d∅/dt    ........1

here ∅ = ( BAcosθ)

so we say angle is zero degree and magnetic filed is uniform here so that

emf = - d ( BAcos0) /dt

emf = - B dA /dt     ..............2

so  area will be

dA/dt = d(πr²) / dt

dA/dt = 2πr dr/dt

we know 2πr = c,

r = c/2π = 165 / 2π

r  = 26.27 cm

c is circumference so from equation 2

emf = - B 2πr dr/dt    ................3

and

here we find rate of change of radius that is

dr/dt = 12/2π = 1.91  10^{-2}cm/s

so when 9.0s have passed that radius of coil = 26.27 - 191 (9)

radius = 9.08 10^{-2} cm

so now from equation 3 we find emf

emf = - (0.500 )  2π(9.08 10^{-2} )   1.91  10^{-2}

emf = - 0.005445

and magnitude of emf = 0.005445 V

so

emf induced is 0.005445 V and direction is clockwise because we can see area is decrease and so that flux also decrease so using right hand rule direction of current here clockwise

4 0
3 years ago
A hot air balloon is filled with 1.45 × 10 6 L of an ideal gas on a cool morning ( 11 ∘ C ) . The air is heated to 109 ∘ C . Wha
just olya [345]

Answer:

<em>The volume of air after the balloon is heated = 1.95 × 10⁶ L</em>

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Charles Law: Charles' law states that the volume of a given mass of gas is directly proportional to the temperature in Kelvin, provided that the pressure remains constant.

It can be expressed mathematically as,

V₁/T₁ = V₂/T₂

Making V₂ The subject of the equation

V₂ = (V₁/T₁)T₂.................... Equation 1

Where V₁ = Initial Volume, T₁ = Initial Temperature, V₂ = Final Volume, T₂ = final Temperature

<em>Given: V₁ = 1.45 × 10⁶ L, T₁ = 11 °C = (11 + 273) K = 284 K, T₂ = 109 °C = (109 + 273) = 382 K.</em>

<em>Substituting these values into equation 1 above,</em>

<em>V₂ = (1.45×10⁶)382/284</em>

<em>V₂ = 1.95 × 10⁶ L</em>

<em>Therefore the volume of air after the balloon is heated = 1.95 × 10⁶ L</em>

6 0
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Vesna [10]
Answer is C. 5 km west
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Olegator [25]

Answer:

a) Transverse and longitudinal

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Depending on the medium in which the sound is traveling the wave can be longitudinal or transverse.

When traveling in fluids i.e., in liquids and gases the wave takes the form of a longitudinal wave. Longitudinal waves cause compression and rarefaction  of the fluid.

When traveling in solids the wave takes the form of a transverse wave. Transverse waves leads to the formation of shear stresses in the solid.

8 0
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