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Darina [25.2K]
3 years ago
8

Select all irrational numbers.

Mathematics
1 answer:
Maurinko [17]3 years ago
5 0

Answer:

OPTION A

OPTION B

OPTION C

Step-by-step explanation:

Irrational numbers are the subset of real numbers. Their decimal representation neither form a pattern nor terminate.

OPTION A: $ \sqrt{\frac{1}{2}} $

This is equal to $ \frac{1}{\sqrt{2}} $.

$ \sqrt{2} = 1.414... $ is non-terminating. So, it is an irrational number. Hence, the reciprocal of an irrational number would also be irrational. So, OPTION A is irrational.

OPTION B: $ \sqrt{\frac{1}{8}} $

This is equal to $ \frac{1}{2\sqrt{2}} $. Using the same logic as Option A, we regard OPTION B to be irrational as well.

OPTION C: $ \sqrt{\frac{1}{10}} $

This is equal to $ \frac{1}{\sqrt{5}\sqrt{2}} $.

Both $ \sqrt{5} $ and $ \sqrt{2} $ are irrational. So, the product and the reciprocal of the product is irrational as well. So, OPTION C is an irrational number.

OPTION D: $ \sqrt{\frac{1}{16}} $

16 is a perfect square and is a rational number. $ \frac{1}{\sqrt{16}} $ = $ \frac{1}{4} $. This is equal to 0.25, a terminating decimal. So, OPTION D is a rational number.

OPTION E: $ \sqrt{\frac{1}{4}} $

4 is a perfect square as well. $ \frac{1}{\sqrt{4}} = \frac{1}{2} = 0.5 $, a terminating decimal. So, OPTION E is a rational number.

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