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2 answers:
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Answer:
a)
b)
c)
Explanation:
Hello,
a) In this case, the given height in cm is:
And the radius in cm is:
Thus, the volume in cubic centimeters which is also equal in mL (1cm³=mL) is:
b) In this case, the given height in mm is:
And the radius in mm is:
Thus, the volume in cubic millimeters is:
c) Finally, since 1000 mL equal 1 L, the required density in g/L turns out:
Best regards.
Answer:
650 mmol.
Explanation:
The equation for the fermentation of one mole of glucose is:
C₆H₁₂O₆ + 2 NAD⁺ + 2 ADP + 2 P i + 2 NADH → 2 EtOH + 2 ATP + 2 NADH + 2 NAD⁺
Since NAD⁺/NADH is used and regenerated, we can eliminate it from the equation:
C₆H₁₂O₆ + 2 ADP + 2 P i → 2 EtOH + 2 ATP
With the equation, we calculate the maximum amount of ethanol that could be obtained theoretically:
1000 mmol C₆H₁₂O₆ ------------ 2000 mmol EtOH
325 mmol C₆H₁₂O₆ ------------- x= 650 mmol EtOH
Therefore, the maximum amount of ethanol that could be produced is 650 mmol.
