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Answer:
a) 6.3 cm
b) 8.0 cm
c) 0.7875
Explanation:
(a) The compound has moved above upto 7.3 cm from the bottom of the paper. Let us assume that line is drawn at 1.0 cm mark as the origin of spot. \
Distance traversed by compound= 7.3 - 1.0 cm = 6.3 cm
(b) Distance traversed by the solvent = 9.0 - 1.0 cm = 8.0 cm
(c) The Rf = Compound Migration distance / Solvent front migration distance
= 6.3/8.0 = 0.7875
Answer:
55.4324℃
Explanation:
Q=cm△t
50J = 0.902J/（g·℃） x 1g x △t
△t =55.4324℃
This deflection of the two hydrogen atoms to one side of the molecule is because of two love pairs of electrons on the other side of the oxygen atoms. In addition, due to the high electronegativity of an oxygen atom (since it has more protons) , it attracts most of the electron cloud of the molecule. The oxygen side of the water molecule is partially negative (negative dipole) while the hydrogen sides are partially positive (positive dipole).
Answer:
The answers are in the explanation
Explanation:
A. For the reaction:
CO(g) + H₂O(g) ⇌ CO₂(g) + H₂(g); ΔH°=−41kJ.
As the reaction is exothermic ( ΔH°<0), you need to use low temperature to increase the equilibrium yield of hydrogen -LeChatelier's principle-.
We would use <em>low </em>temperature. For an <em>exothermic </em>reaction such as this, <em>decreasing </em>temperature increases the value of K and the amount of products at equilibrium.
B.
c. No. We cannot increase the equilibrium yield of hydrogen by controlling the pressure of this reaction.
It is possible to increase the equilibrium yield of reaction by controlling the amount of reactants added. As reactants and products are gases, the pressure of the reaction will not change the amount of reactants or products in the equilibrium.
I hope it helps!
