Answer:
Nuclear fusion is not possible in laboratory as it is performed in high temperature. This cannot be attained in the laboratory.
The reaction produces 6 g of carbon dioxide.
The word equation is
methane + oxygen → carbon dioxide + water
12.2 g + 4 g → x g + 20 g
The <em>Law of Conservation of Mass</em> tells us the total mass of the reactants must equal the mass of the products. Then
12.2 g + 14 g =<em> x</em> g + 20 g
<em>x</em> = 12.2 + 14 – 20 = 6
The mass of carbon dioxide is 6 g.
<em>Note</em>: The answer can have <em>no decimal places</em> because you gave none for the masses of oxygen and water.
Balanced equation:
4 FeS₂ + 11 O₂ --> 2 Fe₂O₃ + 8 SO₂
---
Find the limiting reactant (the one that produces the least amount of product) :
(73.5 g FeS₂) * (1 mole FeS₂ / 119.975 g FeS₂) * (2 moles Fe₂O₃ / 4 moles FeS2) * (159.6882 g Fe₂O₃ / 1 mole Fe₂O₃)
= 48.9 g Fe₂O₃ …………. to 3 sig figs
(44 g O₂) * (1 mole O₂ / 31.9988 g O₂) * (2 moles Fe₂O₃ / 11 moles O₂) *
(159.6882 g Fe₂O₃ / 1 mole Fe₂O₃)
= 40 g Fe₂O₃ ………………. to 2 sig figs
O₂ is the limiting reactant and the theoretical yield is 44 g Fe₂O₃
Mmncotiuy unscrambled would be Community
