Suppose a gas mixture used for anesthesia contains 4.60 mol oxygen (O₂) and 6.00 mol nitrous oxide (N₂O). The total pressure of
1 answer:
Considering the definition of mole fraction, the mole fraction of O₂ in the mixture is 0.434.
<h3>Definition of mole fraction</h3>The molar fraction is a way of measuring the concentration that expresses the proportion in which a substance is found with respect to the total moles of the solution.
In other words, the mole fraction expresses the concentration of solute in a solution as the ratio of moles of substance to total moles of solution:
In this case, you know a gas mixture used for anesthesia contains 4.60 mol oxygen (O₂) and 6.00 mol nitrous oxide (N₂O).
So, the total moles of the solution can be calculated as:
Total moles = moles of oxygen (O₂) + moles of nitrous oxide (N₂O)
Then:
Total moles= 4.60 moles + 6 moles
Total moles= 10.60 moles
Finally, the more fraction of O₂ can be calculated as follow:
Solving:
<u><em>Mole fraction O₂ = 0.434</em></u>
Finally, the mole fraction of O₂ in the mixture is 0.434.
Learn more about mole fraction:
#SPJ1
You might be interested in
Answer:
The choice of the answer is fourth option that is -61 degrees.
Therefore the temperature drop is -61°Centigrade.
Explanation:
Given:
The temperature in a town started out at 55 degrees
Start temperature = 55°Centigrade. (Initial temperature)
End of the Day = -6°Centigrade. (Final temperature)
To Find:
How far did the temperature drop?
Solution:
We will have,
Substituting the above values in it we get
Therefore the temperature drop is -61°Centigrade.
A electrochemical reaction is said to be spontaneous, if 
Answer 1:
Consider reaction: <span>Ni^2+ (aq) + S^2- (aq) ----> + Ni (s) + S (s)
The cell representation of above reaction is given by;
</span>
Hence,
we know that,
and
Therefore,
= - 0.25 - (-0.47) = 0.22 v
Since, is positive, hence cell reaction is spontaneous
.....................................................................................................................
Answer 2:
Consider reaction: <span>Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq)
</span>
The cell representation of above reaction is given by;
Hence,
we know that,
and
Therefore, = - 0.126 - 0 = -0.126 v
Since, is negative, hence cell reaction is non-spontaneous.
....................................................................................................................
Answer 3:
Consider reaction: <span>2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq)
</span>
The cell representation of above reaction is given by;
Hence,
we know that,
and
Therefore, = - 0.22 - (-0.913) = 0.693 v
Since, is positive, hence cell reaction is spontaneous
Answer 1:
Consider reaction: <span>Ni^2+ (aq) + S^2- (aq) ----> + Ni (s) + S (s)
The cell representation of above reaction is given by;
</span>
Hence,
we know that,
and
Therefore,
Since,
.....................................................................................................................
Answer 2:
Consider reaction: <span>Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq)
</span>
The cell representation of above reaction is given by;
Hence,
we know that,
and
Therefore,
Since,
....................................................................................................................
Answer 3:
Consider reaction: <span>2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq)
</span>
The cell representation of above reaction is given by;
Hence,
we know that,
and
Therefore,
Since,