I think b is the right one
Answer:
- The difference in length for steel is 2.46 x 10⁻⁴ m
- The difference in length for invar is 1.845 x 10⁻⁵ m
Explanation:
Given;
original length of steel, L₁ = 1.00 m
original length of invar, L₁ = 1.00 m
coefficients of volume expansion for steel, = 3.6 × 10⁻⁵ /°C
coefficients of volume expansion for invar, = 2.7 × 10⁻⁶ /°C
temperature rise in both meter stick, θ = 20.5°C
Difference in length, can be calculated as:
L₂ = L₁ (1 + αθ)
L₂ = L₁ + L₁αθ
L₂ - L₁ = L₁αθ
ΔL = L₁αθ
Where;
ΔL is difference in length
α is linear expansivity =
Difference in length, for steel at 20.5°C:
ΔL = L₁αθ
Given;
L₁ = 1.00 m
θ = 20.5°C
ΔL = 1 x 1.2 x 10⁻⁵ x 20.5 = 2.46 x 10⁻⁴ m
Difference in length, for invar at 20.5°C:
ΔL = L₁αθ
Given;
L₁ = 1.00 m
θ = 20.5°C
ΔL = 1 x 0.9 x 10⁻⁶ x 20.5 = 1.845 x 10⁻⁵ m
Answer:
The balanced equations are as follows:
✅ FeCl₃ + 3NH₄OH ➡ Fe(OH)₃ + 3NH₄Cl
✅ CH₄ + O₂ ➡ CO₂ + 2H₂O
✅ 2Fe + 3H₂SO₂ ➡ Fe₂(SO₂)₃ + 3H₂
✅ PCl₅ + 4H₂O ➡ 5HCl + H₃PO₄
Explanation:
In the equation, FeCl₃ + 3NH₄OH ➡ Fe(OH)₃ + 3NH₄Cl, Charlie will adjust the number of atoms in NH₄OH in order for NH₄, Cl and OH to balance in the product side. 3 was placed in front of NH₄OH and NH₄Cl in order the balance it.
In the equation, CH₄ + O₂ ➡ CO₂ + 2H₂O, Charlie will adjust the number of atoms in H₂O. 2 was placed in front of H₂O in order to balance the atoms in the reactant and product sides.
In the equation, 2Fe + 3H₂SO₂ ➡ Fe₂(SO₂)₃ + 3H₂, Charlie will adjust the number of atoms in the reactant side in order for the product side to be balanced.
In the equation, PCl₅ + 4H₂O ➡ 5HCl + H₃PO₄, Charlie will adjust the number of atoms in H₂O and HCl for the equation to be balanced. 4 and 5 were placed in front of H₂O and HCl respectively in order for the equation to be balanced.
In chemical equations, it is required that the number of atoms of each element found in the reactants must be equal to the number of atoms of each element found in the products. This makes the chemical equation balanced.
Answer:C) car X
Explanation:
Given
All the cars have identical Engine thus Force Produced by car X will be equal to Y and Z
and
Since Car X is most massive so acceleration associated with it will be minimum
acceleration of car X is minimum thus it will travel farthest