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never [62]
3 years ago
13

An elimination reaction can best be described as a reaction in which an elimination reaction can best be described as a reaction

in which a hydrocarbon reacts with oxygen to produce co2, h2o, and energy. two reactants combine to form one new product with no extra atoms. a single reactant splits into two products. two reactants exchange atoms to give two new products. a single reactant undergoes reorganization of its chemical bonds, producing an isomer of the reactant.
Chemistry
1 answer:
tresset_1 [31]3 years ago
4 0
So I’m not 100% sure what you’re asking but I’m going to give it a go. The elimination reaction is a term used in organic chemistry that describes a type of reactions. The name kinda tells you what’s going to happen. Something is going to be removed/eliminated from initial reactant/substrate and as a result, an alkene (double bond containing compound) will form.

In elimination reactions a hydrogen atom is first removed (as a H+) from the beta carbon. As a result, the left behind electrons create a pi bond between the beta carbon and the neighboring alpha carbon. This promotes the electronegative atom, on the alpha carbon, to leaves the substrate taking both electrons from the shared sigma bond with the alpha carbon.
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To learn more about the genetic material of plant and animal cells, where would a person look?
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6 0
3 years ago
Use the provided reduction potentials to calculate ArGº for the following balanced redox reaction: Pb2+(aq) + Cu(s) → Pb(s) + Cu
nydimaria [60]

Answer : The correct option is, +91 kJ/mole

Solution :

The balanced cell reaction will be,  

Cu(s)+Pb^{2+}(aq)\rightarrow Cu^{2+}(aq)+Pb(s)

Here copper (Cu) undergoes oxidation by loss of electrons, thus act as anode. Lead (Pb) undergoes reduction by gain of electrons and thus act as cathode.

First we have to calculate the standard electrode potential of the cell.

E^0_{[Pb^{2+}/Pb]}=-0.13V

E^0_{[Cu^{2+}/Cu]}=+0.34V

E^0_{cell}=E^0_{cathode}-E^0_{anode}

E^0_{cell}=E^0_{[Pb^{2+}/Pb]}-E^0_{[Cu^{2+}/Cu]}

E^0_{cell}=-0.13V-(0.34V)=-0.47V

Now we have to calculate the standard Gibbs free energy.

Formula used :

\Delta G^o=-nFE^o_{cell}

where,

\Delta G^o = standard Gibbs free energy = ?

n = number of electrons = 2

F = Faraday constant = 96500 C/mole

E^o = standard e.m.f of cell = -0.47 V

Now put all the given values in this formula, we get the Gibbs free energy.

\Delta G^o=-(2\times 96500\times (-0.47))=+90710J/mole=+90.71kJ/mole\approx +91kJ/mole

Therefore, the standard Gibbs free energy is +91 kJ/mole

6 0
2 years ago
What is the correct name for Au3N?
Reptile [31]

Answer:

option D= Gold (I) nitride

Explanation:

The name of the given compound is gold(I) nitride.

Molar mass can be determine by following way:

molar mass Au3N = (molar mass of gold × 3) + (molar mass of nitrogen)

molar mass Au3N = (196.97 × 3 ) + ( 14 )

molar mass of Au3N =  590.91 g/mol + 14 g/mol

molar mass of Au3N = 604.91 g/mol

The nitrogen has valency of -3 so three Au(+1) will require while the valency of Au is (1+) one nitrogen will require to make the compound overall neutral.

Au3N

3(1+) + (-3) = 0

+3 - 3 = 0

0 = 0

The overall charge is 0, the compound will be neutral.

8 0
3 years ago
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laila [671]

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Explanation:

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Answer:

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