When base is added in order to increase the pH of a solution, it results in MOH salt <u>precipitating first.</u>
Equation :
MOH (s) ⇄ M⁺ (aq) ₊ OH⁻(aq)
K
= [M⁺] [OH⁻]
K
= 1.39×10⁻¹² and [M⁺] = 0.001M
∴ 1.39×10⁻¹² = (0.001M) [OH⁻]
[OH⁻] = 1.004×10⁻¹⁹M
pOH = -log [OH⁻] = 11.9
pH = 14 - pOH
= 14 - 11.9
<u>pH = 2.1</u>
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Answer:
was the concentration of the original solution.
Explanation:
(Dilution)
where,
are molarity and volume of non diluted sample.
are molarity and volume of diluted sample.


(1μL=0.001 mL)


Substituting all values :


was the concentration of the original solution.
The ignition occurs when a mixture of fuel & oxygen encounter an external heat source with sufficient heat<u> Piloted ignition.</u>
<h3>
What is Piloted ignition?</h3>
When a volatile fuel is close to a nearby local energy source (pilot) and reaches its lower limit of flammability in air, piloted ignition may be possible. The flame that originates in the premixed system spreads outward from the pilot. The first law of thermodynamics for systems with fixed mass only describes the energetics of this process.
<h3>Definition of thermodynamics </h3>
The science of thermodynamics examines how heat, work, temperature, and energy are related. The general topic of thermodynamics is the transfer of energy from one location or form to another. The fundamental idea is that heat is a type of energy that is equivalent to a specific quantity of mechanical labor.
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The new concentration of the solution is 0.016 M
<h3>Dilution</h3>
From the question, we are to determine the concentration of the new solution prepared from question 4.
NOTE: Question is provided below
From question 4, the concentration of the sodium chloride solution is 0.200M
Now, to determine the new concentration,
Using the dilution law
C₁V₁ = C₂V₂
Where
C₁ is the initial concentration
V₁ is the initial volume
C₂ if the final concentration
and V₂ is the final volume
Then,
C₁ = 0.200 M
V₁ = 10.00 mL
C₂ = ?
V₂ = 125.00 mL
Then,
0.200 × 10.00 = C₂ × 125.00

C₂ = 0.016 M
Hence, the new concentration of the solution is 0.016 M
Question 4:
Calculate the amount of solid sodium chloride needed to make 200.00 mL of a 0.200 M solution
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A because if it remains through the whole expídeme y the same the it doesn’t depend on anything else to change it and I got it correct