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Ghella [55]
3 years ago
12

Can someone help me with the question in the image. if correct i will mark as brainliest

Mathematics
1 answer:
Andrews [41]3 years ago
5 0

Answer: i think its B

Step-by-step explanation:

You might be interested in
How would I simplify and solve for X in this trigonometric equation? (Radians)
Phoenix [80]

Answer:

Please, refer to the images below

Step-by-step explanation:

We need to solve for x in the equation

cos (x+ pi) ^2 = sin (x)

cos (x+ pi) = - cos(x)

(-cos (x)) * (-cos (x)) = sin(x)

cos(x) ^2 = sin(x)

We know that

cos(x) ^2  + sin(x) ^2  = 1

cos(x) ^2 = 1 - sin(x) ^2

1 - sin(x) ^2 = sin(x)

sin(x) ^2 + sin (x) -1 = 0

Let A = sin(x)

A^2 + A - 1 = 0

(solutions attached in picture 1)

This means that

x = arcsin(A)

(solutions attached in picture 2)

8 0
3 years ago
A soccer team is having a car wash. The team spent $45 on supplies. They earned $350, including tips. The team's profit is the a
umka21 [38]

The profit is going to be the total amount made, so you are going to subtract $350 - $45 = $305. $305. I hope this helps!

5 0
4 years ago
What is the ratio of 18 inches to 1 yard? (Change 1 yard to 36 inches before writing the ratio)
Westkost [7]

Answer:

1:2

Step-by-step explanation:

18 inches to 1 yard

We need to convert 1 yard to 36 inches

18 inches : 36 inches

Divide each side by 18

18/18 : 36/18

1:2

8 0
3 years ago
6×_=44. six times what equals 44
BigorU [14]
The answer is 7.333, the threes are ongoing.

To find this answer you would just divide 44 and 6, since you are trying to find groups of the number stated.

Hope that helped.
8 0
4 years ago
a 16 inch wire is to be cut. one piece is to be bent into the shape of a​ square, whereas the other piece is to be bent into the
Lyrx [107]
1. Let x be a length of square side, then the square perimeter is 4x (you need to cut 4x from 16 in. to make a square with side x in.). Then 16-4x is remained length of wire and you have to make form this piece a rectangle with sides one of which is twice bigger than another. If y is length of the smaller side, then 2y is length of the bigger side and rectangle perimeter is y+2y+y+2y=6y. You have 16-4x in. of wire left, so 6y=16-4x and y= \frac{16-4x}{6}.

2.
 A_{square}=x^2 \\ A_{rectangle}=y\cdot 2y=\frac{16-4x}{6}\cdot2\cdot\frac{16-4x}{6}= \frac{(16-4x)^2}{18}  \\ A(x)=A_{square}+A_{rectangle}=x^2+\frac{(16-4x)^2}{18}.

3. Find the derivative of the function A(x): 
A'(x)=2x+ \dfrac{2(16-4x)\cdot(-4)}{18} =2x- \dfrac{4(16-4x )}{9}.

4. Solve the equation A'(x)=0: 
2x- \dfrac{4(16-4x )}{9}=0 \\ 18x-64+16x=0 \\ 34x=64 \\ x= \frac{32}{17}

5. Since y= \frac{16-4x}{6} you have

y= \dfrac{16-4 \frac{32}{17} }{6} = \dfrac{16\cdot17-4\cdot32}{6\cdot 17} = \dfrac{24}{17}.

Answer: <span>the width of the rectangle is \frac{24}{17}</span>




6 0
4 years ago
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