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3 years ago

Which formula equation represents the burning of sulfur to produce sulfur dioxide?

Chemistry

2 answers:

alexdok [17]3 years ago

7 0

Answer:

$S_{(g)}+O_2_{(g)}\rightarrow SO_2_{(g)}$

Explanation:

Sulfur in the pressure of oxygen produces sulfur dioxide gas. The balanced chemical reaction is shown below as:-

$S_{(g)}+O_2_{(g)}\rightarrow SO_2_{(g)}$

The enthalpy change of the reaction is ΔH = -297 kJ/mol. This burning of sulfur reaction is exothermic in nature and this combustion can produce temperature of upto 1000 °C or more.

Sulfur in the elemental state oxidises and changes its oxidation number from 0 to +4 and oxygen reduces and changes its oxidation number from 0 to -2.

Firlakuza [10]3 years ago

6 0

Balanced chemical equation: S(s) + O₂(g) → SO₂(g).

Sulfur change oxidation number from 0 to +4 (oxidation) and oxygen change oxidation number from 0 to -2 (reduction).

Sulfur dioxide (SO₂) is very common volcanic gas.

Fossil fuel combustion increases the acidity of rain because the sulfur dioxide is produced.

Because of fuel combustion, sulfur dioxide goes up into the atmosphere as the hot gases rise, than it reacts with water and oxygen in the air and form sulfuric acid.

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Which element would lose electrons during ionic bonding choose all that apply

yawa3891 [41]

Answer:

All of them!

Explanation:

Since Mg, Li, Ca, and Cs are all in groups 1 and 2 of the periodic table, they are alkali/alkaline earth metals and will all lose electrons during ionic bonding.

7 0

3 years ago

An unknown salt is either NaF, NaCl, or NaOCl. When 0.050 mol of the salt is dissolved in water to form 0.500 L of solution, the

victus00 [196]

Answer: The unknown salt is NaF

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles of salt = 0.050 moles

Volume of solution = 0.500 L

Putting values in above equation, we get:

$\text{Molarity of salt}=\frac{0.050mol}{0.500L}\\\\\text{Molarity of salt}=0.1M$

To calculate the hydroxide ion concentration, we first calculate pOH of the solution, which is:

pH + pOH = 14

We are given:

pH = 8.08

$pOH=14-8.08=5.92$

To calculate pOH of the solution, we use the equation:

$pOH=-\log[OH^-]$

Putting values in above equation, we get:

$5.92=-\log[OH^-]$

$[OH^-]=10^{-5.92}=1.202\times 10^{-6}M$

The unknown salt given are formed by the combination of weak acid and strong acid which is NaOH

The chemical equation for the hydrolysis of $X^-$ ions follows:

$X^-(aq.)+H_2O(l)\rightleftharpoons HX(aq.)+OH^-(aq.);K_b$

Initial: 0.1

At eqllm: 0.1-x x x

Concentration of $OH^-=x=1.202\times 10^{-6}M$

The expression of $K_b$ for above equation follows:

$K_b=\frac{[OH^-][HX]}{[X^-]}$

Putting values in above expression, we get:

$K_b=\frac{(1.202\times 10^{-6})\times (1.202\times 10^{-6})}{(1-(1.202\times 10^{-6}))}\\\\K_b=1.445\times 10^{-11}M$

To calculate the acid dissociation constant for the given base dissociation constant, we use the equation:

$K_w=K_b\times K_a$

where,

$K_w$ = Ionic product of water = $10^{-14}$

$K_a$ = Acid dissociation constant

$K_b$ = Base dissociation constant = $1.445\times 10^{-11}$

Putting values in above equation, we get:

$10^{-14}=1.445\times 10^{-11}\times K_a\\\\K_a=\frac{10^{-14}}{1.445\times 10^{-11}}=6.92\times 10^{-4}$

We know that:

$K_a\text{ for HF}=6.8\times 10^{-6}$

$K_a\text{ for HCl}=1.3\times 10^{6}$

$K_a\text{ for HClO}=3.0\times 10^{-8}$

So, the calculated $K_a$ is approximately equal to the $K_a$ of HF

Hence, the unknown salt is NaF

6 0

3 years ago

Which elements can form acidic compounds?

pashok25 [27]

Sodium and magnesium oxides are alkaline. Aluminium oxides are amphoteric (reacting both as a base or acid). Silicon, phosphorus, sulfur, and chlorine oxides are acidic. Some non-metal oxides, such as nitrous oxide (N2O) and carbon monoxide (CO), do not display any acid/base characteristics.

7 0

3 years ago

Read 2 more answers

How does lacquer thinner work chemically?

Anton [14]

Have a nice day today

8 0

3 years ago

The students in the picture below are using a globe and a lamp to model the Sun and the Earth. If the model Earth acts the same

timofeeve [1]

Answer:

The only one that makes sense IF the model behaves as the Earth is D.