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Brrunno [24]
2 years ago
11

How should you remove a beaker from a hot plate after heating it?.

Chemistry
1 answer:
ohaa [14]2 years ago
3 0

Answer:

<em>One of the students should place a wire gauze on the lab station to set the beaker on. Using the beaker tongs, one of the students should gently remove the beaker from the hot plate and set it down on to the wire gauze.</em>

Explanation:

<em>I </em><em>hope</em><em> it</em><em> will</em><em> help</em><em> you</em><em>.</em><em>.</em><em>.</em>

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PLEASE HELP!!
Andrews [41]
The answer should be B. hope this helped ;)
3 0
3 years ago
Please help, answer questions 3-7
tatyana61 [14]
I don’t know about 3 but I know that 4 is solid, 5 is you’ll feel the vibration first, 6 is you’ll see the lightning first because the speed of light is faster than the speed of sound and 7 is sound waves need a medium to travel and light waves don’t, sound waves are longitudinal and light waves are transverse, and sound waves are mechanical waves while light waves are electromagnetic waves
3 0
3 years ago
If irons temperature goes from 50c to 75c in a 20g sample, how many joules of heat were used?
Marina CMI [18]

Answer:

Option D. 230 J

Explanation:

We'll begin by calculating the temperature change of the iron. This can be obtained as follow:

Initial temperature (T₁) = 50 °C

Final temperature (T₂) = 75 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 75 – 50

ΔT = 25 °C

Thus, the temperature change of the iron is 25 °C.

Finally, we shall determine the amount of heat energy used. This can be obtained as follow:

Mass (M) = 20 g

Change in temperature (ΔT) = 25 °C

Specific heat capacity (C) = 0.46 J/gºC

Heat (Q) =?

Q = MCΔT

Q = 20 × 0.46 × 25

Q = 230 J

Thus, the amount of heat used was 230 J

3 0
3 years ago
Transuranium elements are artificial and may be prepared by a fusion process in which heavy nuclei are bombarded with light ones
Scilla [17]

Answer:

_{97}^{345}\textrm{Bk}

Explanation:

In a nuclear reaction, the total mass and total atomic number remains the same.

Am has an atomic number of 95. So correct reaction is:-

^{343}_{95}\textrm{Am}+^{4}_{2}\textrm{He}\rightarrow ^A_Z\textrm{X}+2^1_0\textrm{n}

To calculate A:

Total mass on reactant side = total mass on product side

343 + 4 = A + 2

A = 345

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

95 + 2 = Z + 0

Z = 97

Hence, the isotopic symbol of unknown element is _{97}^{345}\textrm{Bk}

7 0
3 years ago
The saltwater is a homogeneous or a heterogeneous mixture
ddd [48]
Homogeneous because it is unable to be distinguished of the components Water and Salt
5 0
3 years ago
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