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3 years ago

What quantum number of the hydrogen atom comes closest to giving a 24-nm-diameter electron orbit?

Chemistry

1 answer:

Paraphin [41]3 years ago

4 0

n = 15. A Bohr orbit with n = 15 comes closest to having a 24 nm diameter .

The formula for the radius r of the nth orbital of a hydrogen atom is

r = n^2·a

where

a = the Bohr radius = 0.0529 nm

We can solve this equation to get

n = √ (r/a)

If d = 24 nm, r = 12 nm.

∴ n = √(12 nm/0.0529 nm) = √227 = 15.1

n must be an integer, so n = 15.

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When matter it gains energy and changes from a solid to a liquid as the particles move faster and the bonds holding the pattern

andrezito [222]

When you heat up the matter, it gains energy and the bonds are broken. Then it will make solid become liquid

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3 years ago

What is the ph of an acetic acid solution if 10 drops are titrated with 70 drops of a 0.65 m koh solution? (ka for acetic acid =

laiz [17]

What is the ph of an acetic acid solution if 10 drops are titrated with 70 drops of a 0.65 m koh solution? (ka for acetic acid = 1.8 x 10-5)?

[KOH] = 0.65 M
[OH] = 0.65 M
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7 0

3 years ago

Infer why the brown marmarated stink bug (BMSB) is an invasive species in the United States.

Anna71 [15]

Answer:

A. China And Japan.

Explanation:

The species is native to China/Japan and was introduced into the United States in the mid-1990s, possibly stowing away in a shipping container. The presence of this stink bug is concerning for farmers because it feeds on a large number of high-value crops and ornamental plants in its immature and adult life stages.

3 0

2 years ago

Calculate the total volume of gas (at 119 ?c and 731 mmhg produced by the complete decomposition of 1.71 kg of ammonium nitrate.

Shtirlitz [24]

The reaction is:

NH4 (NO3) (s) ⇄ N2O (g) + 2 H2O (g)

This means that 1 mol of NH4 (NO3)s produces 3 moles of gases.

Now find the number of moles in 1.71 kg of NH4 (NO3)

Molar mass = 2*14g/mol + 4 * 1g/mol + 3*16g/mol = 80 g/mol

# moles = mass / molar mass = 1710 g / 80 g/mol = 21.375 mol of NH4(NO3)

We already said that every mol of NH4(NO3) produces 3 moles of gases, then the number of moles of gases produced is 3 * 21.375 = 64.125 mol

Now use the equation for ideal gases to fin the volume

pV = nRT => V = nRT / p = (64.125 mol)(0.082atm*liter / K*mol) * (119 +273)K / (731mmHg *1 atm/760mmHg) =

V = 2143.01 liters

4 0

3 years ago

Given that Delta. G for the reaction below is –957. 9 kJ, what is Delta. Gf of H2O? 4NH3(g) 5O2(g) Right arrow. 4NO(g) 6H2O(g) D

vesna_86 [32]

ΔG for the formation of H₂O is -228.6 kJ.

<h3>How we calculate Gibb's free energy of the reaction?</h3>

Gibb's free energy of the reaction is calculated as:

ΔG = G for product - G for reactant

Given chemical reaction is:

4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(g)

In the question, given that:

ΔG for the reaction = -957. 9 kJ

ΔGf of NH₃ = -16. 66 kJ/mol

ΔGf of NO = 86. 71 kJ/mol

Equation for ΔG will be written as:

ΔG = (ΔGf of NO + ΔGf of H₂O) - (ΔGf of NH₃+ ΔGf of O₂)

ΔGf of O₂ = 0

-957. 9 = (4×86. 71 + 6×ΔGf of H₂O) - (4×-16. 66 + 5×ΔGf of O₂)

-957. 9 = 346.84 + 6ΔGf of H₂O + 66.64

ΔGf of H₂O = (-957. 9 - 346.84 - 66.64) / 6

ΔGf of H₂O = -228.56 kJ ≅ -228.6 kJ

Hence, option (1) is correct i.e. -228.6 kJ is the ΔGf of H₂O.

To know more about Gibb's free energy, visit the below link:

brainly.com/question/14415025

6 0

2 years ago