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-Dominant- [34]
3 years ago
12

The tube that stores sperm cells

Chemistry
2 answers:
mamaluj [8]3 years ago
8 0

Answer:

Vas deferens.

Explanation:

A long tube that is located near each testicle. The epididymis is the tube which moves the sperm from the testicles. Vas deferens. This is a tube in which the sperm is stored and it carries the sperm out of the scrotal sac.

JulsSmile [24]3 years ago
5 0

Answer:

here is the answer

Explanation:

The epididymis

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Changes to the global climate could include _______.
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1. Answer is d. all of the above.

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2. Answer is c. ozone.

Trees release oxygen and water vapor into the atmosphere but not ozone. The oxygen gas is released by trees as the by-product of photosynthesis. This is the natural way of production of oxygen gas. Water vapor can be released due to the transpiration of trees.

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To 225 mL of a 0.80M solution of KI, a student adds enough water to make 1.0L of a more dilute KI solution. What is the molarity
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Fluorine-18 is produced by reacting oxygen-18 with a proton, 11p. The products of this reaction are fluorine-18, a neutron, and
Tanya [424]

₈O¹⁸ + ₁¹H(proton) ⇒ ₉F¹⁸ + ₀n¹(neutron) + ₀γ⁰ (gamma)

<h3>Further explanation</h3>

Given

Fluorine-18

Oxygen-18

Required

Nuclear equation

Solution

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

  • alpha α particles ₂He⁴
  • beta β ₋₁e⁰ particles
  • gamma particles ₀γ⁰
  • positron particles ₁e⁰
  • neutron ₀n¹

The principle used is the sum of the atomic number and mass number before and after the decay reaction is the same

The reaction

₈O¹⁸ + ₁¹H(proton) ⇒ ₉F¹⁸ + ₀n¹(neutron) + ₀γ⁰ (gamma)

7 0
3 years ago
Calculate the equilibrium constant at 298 K for the reaction of formaldehyde (CH2O) with hydrogen gas using the following inform
Mariana [72]

Answer:

E. 8.08 x 10⁴.

Explanation:

Hello,

In this case, for the reaction:

CH_2O(g) + 2H_2(g)  \rightleftharpoons CH_4(g) + H_2O(g)

We can compute the Gibbs free energy of reaction via:

\Delta G\°=\Delta H\°-T\Delta S\°

Since both the entropy and enthalpy of reaction are given at 298 K (standard temperature), therefore:

\Delta G\°=-94.9kJ-(298K)(-224.2\frac{J}{K}*\frac{1kJ}{1000kJ} )\\\\\Delta G\°=-28.1kJ

Then, as the equilibrium constant is computed as:

K=exp(-\frac{\Delta G\°}{RT} )

We obtain:

K=exp(-\frac{-28.1kJ/mol}{8.314x10^{-3}\frac{kJ}{mol* K}}*298K )\\\\K=8.08 x10^4

For which the answer is E. 8.08 x 10⁴.

Best regards,

3 0
4 years ago
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