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2 years ago

So I'm struggling with rearranging kinematic formulas. Does anyone have any steps or something to help.

1 answer:

7 0

Rearranging formulas is all about simple algebra rules. Just like when solving for x in an equation, you're just isolating whichever variable you want. I'll work this one out for you and hopefully it'll help, but if you need more explanation, then feel free to comment!

D = ViT + 0.5at² Subtract ViT from both sides

D - ViT = 0.5at² Divide both sides by 0.5t²

$\frac{D - ViT}{0.5t^{2} } = \frac{0.5at^{2} }{0.5t^{2} }$ I wrote this step out a little more to show how your fraction will cancel

$\frac{D - ViT}{0.5t^{2} }$ = a I like to flip these around so the single variable is on the right

a = $\frac{D - ViT}{0.5t^{2} }$

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2 years ago

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3 years ago

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To understand the nature of electric fields and how to draw field lines. Electric field lines are a tool used to visualize elect

Brrunno [24]

Explanation:

The electric field is defined as the change in the properties of space caused by the existence of a positively (+) or negatively (-) charged particle. The electric field can be represented by infinitely many lines from a particle, and those lines never intersect each other. Depending on the type of charge we can see different cases:

Let's say we have a positive charge alone (image 1). The field lines are drawn from the centre of the particle outwards to infinity (in other words, they disappear from the edge of the picture). Meaning the direction of the electric field points outwards the particle.

For a negative charge alone (image 2), the lines come from infinity to the centre, and point towards the particle (i.e. lines appear from the edge of the picture).

Let's see what happens if we have two charges together:

Two positive charges (image 3): Since the charges are of the same type (positive), the particles repel each other. Then the field lines will avoid each other so they do not join. The charge is positive, so lines point outwards.
Two negative charges (image 4): Again, the charges are both negative, so they repel. But they are negative, so the field points inwards.
Negative and positive charges (image 5): They are different charges, so the force between them is attractive. This causes the field lines from both to join. They go out of the positive and come into the negative particle.

Image 6:

The lines are passing through infinite points of the space. If we choose a certain point and measure the electric field, we can see to which direction the electric field points. This is the direction of the electric field vector. It does not matter which point we choose; the electric field vector touches the field line only at this point, which means it is tangent to the field line.

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3 years ago

An 8.5-l tire is filled with 0.55 mol of gas at a temperature of 305 k. what is the pressure of the gas in the tire?

const2013 [10]

Answer:

1.62 atm

Explanation:

We can solve the problem by using the ideal gas equation:

$pV=nRT$

where:

p = ? is the pressure of the gas in the tire

V = 8.5 L is the volume of the tire

n = 0.55 mol is the number of moles of the gas

R = 0.0821 atm L / K mol is the gas constant

T = 305 K is the temperature of the gas

By re-arranging the equation and substituting the numbers in, we find:

$p=\frac{nRT}{V}=\frac{(0.55 mol)(0.0821 Latm/Kmol)(305 K)}{8.5 L}=1.62 atm$

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3 years ago

Two wheels have the same mass and radius of 4.2 kg and 0.42 m, respectively. One has (a) the shape of a hoop and the other (b) t

andrew-mc [135]

Answer:

τsolid = 0.15 N•m

τhoop = 0.30 N•m

Explanation:

θ = ½αt²

α = 2θ/t² = 2(14)/8.3² = 0.406445 rad/s²

Solid disk I = ½mr² = ½(4.2)0.42² = 0.37044 kg•m²

τ = Iα = 0.37044(0.406445) = 0.150563... N•m

Hoop disk I = mr² = (4.2)0.42² = 0.74088 kg•m²

τ = Iα = 0.74088(0.406445) = 0.301127... N•m

4 0

2 years ago