Answer:
8 mol of hydrogen will react with 1 mol of sulfur.
Explanation:
We'll begin by writing the balanced equation for the reaction.
This is given below:
8H2 + S8 —> 8H2S
Now, let us carefully observe the mole ratio of the reactants.
This is illustrated:
The mole ratio of the reactants ( i.e H2 and S8) is 8 : 1
From the balanced equation above,
We can thus, concluded that:
8 moles of H2 will reacted with 1 mole of S8.
The mass of carbon dioxide that would be produced will be 22 kg
<h3>Combustion of carbon</h3>
The combustion of carbon in air can be represented by the equation:
C + O2 ---> CO2
The mole ratio of C to O2 to CO2 is 1:1:1.
Mole of 6kg of carbon = mass/molar mass
= 6000/12
= 500 moles
Equivalent mole of CO2 produced = 500 moles
Mass of 500 moles CO2 = mole x molar mass
= 500 x 44.01
= 22,005 g or 22 kg approximately
More on combustion reactions can be found here: brainly.com/question/13649083
Answer:
Explanation:
16. 12
17. 8
18. 9
19. 10
20. 5
21. 15
22.8
23. 24
24. 12
25. 3 i guess( some one comment for 25th pls)
26. 2
good sir it seems your answer appears to be B
