Answer:
Theoretical yield = 2.5 g
Explanation:
Given data:
Mass of sodium = 79.7 g
Mass of water = 45.3 g
Theoretical yield of hydrogen gas = ?
Solution:
Chemical equation:
2Na + 2H₂O → 2NaOH + H₂
Number of moles of sodium:
Number of moles = mass/ molar mass
Number of moles = 79.7 g / 23 g/mol
Number of moles = 3.5 mol
Number of moles of water:
Number of moles = mass/ molar mass
Number of moles = 45.3 g / 18g/mol
Number of moles = 2.5 mol
Now we will compare the moles of hydrogen gas with water and sodium.
H₂O : H₂
2 : 1
2.5 : 1/2×2.5 =1.25 mol
Na : H₂
2 : 1
3.5 : 1/2×3.5 =1.75 mol
water will be limiting reactant.
Theoretical yield:
Mass = number of moles × molar mass
Mass = 1.25 mol × 2 g/mol
Mass = 2.5 g
Molarmass of <span>Zn(C2H3O2)4 is 301.5561 g/mol
moles of </span>
<span>Zn(C2H3O2)4
= 62 g * 1 mol/(</span><span>301.5561 g) = 0.2056 mol
concentration = moles / volume
concentration * volume = moles
volume = moles / concentration
volume = 0.2056 mol / 1.5 M
volume = 0.13706 L
volume = 137 mL
volume = 140 mL
</span>
Answer:

Explanation:
Considering the Henderson- Hasselbalch equation for the calculation of the pH of the acidic buffer solution as:
![pH=pK_a+log\frac{[salt]}{[acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2Blog%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D)
Given that:-
[Acid] = 0.12 M
Volume = 3.0 L
pKa = 3.74
pH = 5.30
So,
![5.30=3.74+log\frac{[sodium\ formate]}{0.12}](https://tex.z-dn.net/?f=5.30%3D3.74%2Blog%5Cfrac%7B%5Bsodium%5C%20formate%5D%7D%7B0.12%7D)
Solving, we get that:-
[Sodium formate] = 4.36 M
Considering:

So,

So, Moles of sodium formate = 4.36*3.0 moles = 13.08 moles
Molar mass of sodium formate = 68.01 g/mol
The formula for the calculation of moles is shown below:

Thus,


Biotic Resources are based on living organisms. These are obtained from
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themselves!
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from lithosphere, atmosphere and hydrosphare. Examples are water, air,
minerals. They cannot reproduce themselves.