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2 years ago

12

(True or False) It would be most appropriate to use the noble gas core [He] when writing the shorthand electron configuration fo

r sulfur.

2 answers:

wel2 years ago

8 0

No it should be Ne as it is its closest noble gas.

slamgirl [31]2 years ago

7 0

The answer is false.<span />

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Help, quick, pls<br> What is a displacement reaction?

Andrei [34K]

$\begin{aligned} -5x+4y &= 3\\\\ x&=2y-15 \end{aligned}$

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2 years ago

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4.2 L of a gas has a pressure of 560mmHg at 72⁰F. What is the temperature at760mmHg if the volume is still 4.2 L? (5 pts)

IgorLugansk [536]

Answer:

The temperature at 760mmHg if the volume is still 4.2 L is 400.862 K

Explanation:

Gay Lussac's law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. This law can be expressed mathematically as follows:

$\frac{P}{T} =k$

Having an initial state 1 and a final state 2, the following is true:

$\frac{P1}{T1} =\frac{P2}{T2}$

In this case:

P1= 560 mmHg
T1= 72 F= 295.372 K (being 32 F= 273.15 K)
P2= 760 mmHg
T2= ?

Replacing:

$\frac{560 mmHg}{295.372 K} =\frac{760 mmHg}{T2}$

Solving:

$T2= 760 mmHg*\frac{295.372 K}{560 mmHg}$

T2= 400.862 K

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2 years ago

A 100 mL reaction vessel initially contains 2.60×10^-2 moles of NO and 1.30×10^-2 moles of H2. At equilibrium the concentration

Sliva [168]

Answer:

<h2>The equilibrium constant Kc for this reaction is 19.4760</h2>

Explanation:

The volume of vessel used= $100$ ml

Initial moles of NO= $\frac{2.60}{10^2}$ moles

Initial moles of H2= $\frac{1.30}{10^2}$ moles

Concentration of NO at equilibrium= $0.161$ M

$Concentration(in M)=\frac{moles}{volume(in litre)}$

Moles of NO at equilibrium= $0.161(\frac{100}{1000})$

= $\frac{1.61}{10^2}$ moles

2H2 (g) + 2NO(g) <—> 2H2O (g) + N2 (g)

<u>Initial</u> :1.3*10^-2 2.6*10^-2 0 0 moles

<u>Equilibrium</u>:1.3*10^-2 - x 2.6*10^-2-x x x/2 moles

∴ $\frac{2.60}{10^2}-x=\frac{1.61}{10^2}$

⇒ $x=\frac{0.99}{10^2}$

$Kc=\frac{[H2O]^2[N2]}{[H2]^2[NO]^2} (volume of vesselin litre)$

<u>Equilibrium</u>:0.31*10^-2 1.61*10^-2 0.99*10^-2 0.495*10^-2 moles

⇒ $Kc=\frac{(0.0099)^2(0.00495)}{(0.0031)^2(0.0161)^2} (0.1)$

⇒ $Kc=19.4760$

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2 years ago

The reaction C4H10 ---> C2H6 + C2H4 has activation energy (Ea) of 450 kJ/mol, and the Ea of the reverse reaction is 250 kJ/mo

liraira [26]

Answer:

ΔH = 200 kJ/mol

Explanation:

Step 1: Data given

activation energy (Ea) is: 450 kJ/mol

activation energy (Ea) of the reverse reaction is 250 kJ/mol

Step 2: The balanced equations

C4H10 ---> C2H6 + C2H4 Ea = 450 kJ/mol

C2H6 + C2H4 ---> C4H10 Ea = 250 kJ/mol

Step 3: Calculate ΔH

Since the reverse reaction has a lower activation energy, this means we need less reaction for the reverse reaction to happen. We can say the reaction absorbs energy, so this is the endothermic reaction.

Ea ( of the forward reaction) = ΔH + Ea (of the reverse reaction)

ΔH = Ea ( of the forward reaction) - Ea (of the reverse reaction)

ΔH = 450 kJ/mol - 250 kJ/mol

ΔH = 200 kJ/mol

Since the reactionis endothermi, ΔH is positive

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2 years ago

How many double bonds are in an alkane?

Valentin [98]

None they only have one bond

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2 years ago

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