Answer/explanation:
Product identifier – the brand name, chemical name, common name, generic name or trade name of the hazardous product.
Initial supplier identifier – the name, address and telephone number of either the Canadian manufacturer or the Canadian importer.
The lithosphere makes up the layer of the earth.
Answer: There are
of gas are in a container with a volume of 9.55 mL at 35 °C and a pressure of 895 mmHg
Explanation:
According to ideal gas equation:
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
P = pressure of gas = 895 mm Hg= 1.18 atm (760 mm Hg= 1 atm)
V = Volume of gas = 9.55 ml = 0.00955 L (1 L=1000ml)
n = number of moles = ?
R = gas constant =![0.0821Latm/Kmol](https://tex.z-dn.net/?f=0.0821Latm%2FKmol)
T =temperature =![35^0C=(35+273)K=308K](https://tex.z-dn.net/?f=35%5E0C%3D%2835%2B273%29K%3D308K)
![n=\frac{PV}{RT}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7BPV%7D%7BRT%7D)
![n=\frac{1.18atm\times 0.00955L}{0.0821L atm/K mol\times 308K}=4.46\times 10^{-4}moles](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B1.18atm%5Ctimes%200.00955L%7D%7B0.0821L%20atm%2FK%20mol%5Ctimes%20308K%7D%3D4.46%5Ctimes%2010%5E%7B-4%7Dmoles)
Thus there are
of gas are in a container with a volume of 9.55 mL at 35 °C and a pressure of 895 mmHg
Answer:
I don't know I'm sorry I will tell you another answer asks me to
Answer:
V₂ = 2.91 L
Explanation:
Given data:
Initial volume = 3.50 L
Initial temperature = 90.0°C (90+273 = 363 K)
Final temperature = 30.0 °C ( 30 +273 = 303 K)
Final volume = ?
Solution:
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
V₁/T₁ = V₂/T₂
3.50 L / 363 K) = V₂ / 303 K)
V₂ = 0.0096 L/K × 303 K
V₂ = 2.91 L