Answer: 51 grams
Explanation:
Ammonia is a gas with a chemical formula of NH3.
Given that,
Amount of moles of NH3 (n) = ?
Volume of NH3 (v) = 200mL
since the standard unit of volume is liters, convert 200mL to liters
(If 1000mL = 1L
200mL = 200/1000 = 0.2L)
Concentration of NH3 (c) = 1.5M
Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence
c = n / v
Make n the subject formula
n = c x v
n = 1.50M x 0.2L
n = 3 moles
Now, calculate the mass of ammonia
Amount of moles of NH3 (n) = 3
Mass of NH3 in grams = ?
For molar mass of NH3, use the atomic masses:
N = 14g; H = 1g
NH3 = 14g + (1g x 3)
= 14g + 3g
= 17g/mol
Since, n = mass in grams / molar mass
3 moles = m / 17g/mol
m = 3 moles x 17g/mol
m = 51 grams
Thus, 51 grams of ammonia was dissolved in the solution.
The molar mass of the gas that has a mass of 3.82 g and occupies a volume of 0.854 L is 106.66g/mol.
<h3>How to calculate molar mass?</h3>
The molar mass of a substance can be calculated by dividing the mass of the substance by its number of moles.
However, the number of moles of the gas in this question needs to be calculated first using the ideal gas law equation:
PV = nRT
Where;
- P = pressure
- V = volume
- n = number of moles
- T = temperature
- R = gas law constant
1.04 × 0.854 = n × 0.0821 × 302
0.888 = 24.79n
n = 0.888/24.79
n = 0.036mol
Molar mass of gas = 3.82g/0.036mol
Molar mass = 106.66g/mol
Therefore, the molar mass of the gas that has a mass of 3.82 g and occupies a volume of 0.854 L is 106.66g/mol.
Learn more about molar mass at: brainly.com/question/12127540
Answer: I dont really know
Explanation:
Step 1: Specify the Null Hypothesis. ...
Step 2: Specify the Alternative Hypothesis. ...
Step 3: Set the Significance Level (a) ...
Step 4: Calculate the Test Statistic and Corresponding P-Value. ...
Step 5: Drawing a Conclusion.
