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2 years ago

Given the reaction below, which is the being reduced? Mg Cl2 Right arrow. Mg2 2Cl– 2CI– CI2 Mg Mg2.

Chemistry

1 answer:

Jlenok [28]2 years ago

3 0

The element that has been reduced in the chemical equation is $\rm Cl_2$ .

The given reaction has been:

$\rm Mg\;+\;Cl_2\;\rightarrow\;Mg^2^+\;+\;2\;Cl^-$

The reaction has been the redox reaction, in which the one of the reactant has been oxidized, and the other has been reduced in the chemical reaction.

<h3>Reduction in the reaction</h3>

The reduction has been defined as the gain of electrons. In the given reaction, the Mg loses 2 electrons and has been converted to the Mg ion.

Thus, Mg has been oxidized in the reaction.

The Cl has been present as the diatomic molecule and with the gain of two electrons from the Mg it has been converted to two chloride ions.

Thus, the element that has been reduced in the chemical equation is $\rm Cl_2$ .

Learn more about reduction, here:

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Given the two reactions PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq), K3 = 1.84×10−10, and AgCl(aq)⇌Ag+(aq)+Cl−(aq), K4 = 1.14×10−4, what is the

Nimfa-mama [501]

Answer: The value of equilibrium constant for reaction is, $1.42\times 10^{-2}$

Explanation:

The given chemical equations are:

(1) $PbCl_2(aq)\rightleftharpoons Pb^{2+}(aq)+2Cl^-(aq)$ ; $K_3=1.84\times 10^{-10}$

(2) $AgCl(aq)\rightleftharpoons Ag^{+}(aq)+Cl^-(aq)$ ; $K_4=1.14\times 10^{-4}$

Now we have to calculate the equilibrium constant for chemical equation as:

$PbCl_2(aq)+2Ag^{+}(aq)\rightleftharpoons 2AgCl(aq)+Pb^{2+}(aq)$ ; $K=?$

We are reversing reaction 2 and multiplying reaction 2 by 2 and then adding both reaction, we get the final reaction.

The equilibrium constant for the reverse reaction will be the reciprocal of that reaction.

If the equation is multiplied by a factor of '2', the equilibrium constant of that reaction will be the square of the equilibrium constant.

If we are adding equations then the equilibrium constants will be multiplied.

The value of equilibrium constant for reaction is:

$K=(\frac{1}{K_4})^2\times K_3$

Now put all the given values in this expression, we get:

$K=(\frac{1}{1.14\times 10^{-4}})^2\times (1.84\times 10^{-10})$

$K=1.42\times 10^{-2}$

Hence, the value of equilibrium constant for reaction is, $1.42\times 10^{-2}$

7 0

3 years ago

What is the wavelength range,in nanometer,for infrared light? In what portion of this range does the earth receive IR from the s

andrezito [222]

The wavelength range of Infrared radiation is 700 nanometers to 1 millimeter.
The sun emits mainly near-infrared which is mainly composed of wavelength below 4 micrometers.
The thermal range of infrared ranges between wavelengths 3.5 and 2.0 micrometers

Explanation:

The wavelength range of Infrared radiation is 700 nanometers to 1 millimeter. This also translates to a frequency range of 430 TeraHertz to 300 Giga Hertz.

Because the sun is a star and is hot in comparison to earth and other planetary bodies, the bigger range of infrared radiation it emits is in the near-infrared which is mainly composed of wavelength below 4 micrometers.

The earth's surface produces infrared radiation of the mid-infrared range while cooler substances will produce far-infrared range

The thermal range of infrared ranges between wavelengths 3.5 and 2.0 micrometers and is produced by black bodies.

Learn More:

For more on infrared radiation check out;

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7 0

3 years ago

Using what you have learned about magnetic forces, potential and kinetic energy. Describe the changes

weeeeeb [17]

Answer:

reversible reaction or covalent bonds

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2 years ago

Green plants use light from the Sun to drive photosynthesis, a chemical reaction in which liquid water and carbon dioxide gas fo

Luda [366]

Answer:

0.800 mol of O2

Explanation:

Calculate the moles of oxygen produced by the reaction of 0.800mol of carbon dioxide.

The balanced equation for the reaction is given as;

6CO2 + 6H2O → C6H12O6 + 6O2

From the reaction;

6 mol of CO2 produces 6 mol of O2

0.0800 mol of CO2 would produce x mol of O2

6 = 6

0.0800 = x

Solving for x;

x = 6 * 0.800 / 6

x = 0.800 mol

5 0

2 years ago

Given: logK=nE∘0.0592 What is the value K for this redox reaction? Zn2+(aq) + 2 Cl−(aq) → Zn(s) + Cl2(

anygoal [31]

K = 2.4 × 10^(-72)

Step 1. Determine the value of n

Zn^(2+) + 2e^(-) → Zn

2Cl^(-) → Cl_2 + 2e^(-)

Zn^(2+) + 2Cl^(-) → Zn + Cl_2

∴ n = 2

Step 2. Calculate K

logK = nE°/0.0592 V = [2 × (-2.12 V)]/0.0592 V = -71.62

K = 10^(-71.62) = 2.4 × 10^(-72)

8 0

3 years ago