Given the reaction below, which is the being reduced? Mg Cl2 Right arrow. Mg2 2Cl– 2CI– CI2 Mg Mg2.
1 answer:
The element that has been reduced in the chemical equation is .
The given reaction has been:
The reaction has been the redox reaction, in which the one of the reactant has been oxidized, and the other has been reduced in the chemical reaction.
<h3>Reduction in the reaction</h3>The reduction has been defined as the gain of electrons. In the given reaction, the Mg loses 2 electrons and has been converted to the Mg ion.
Thus, Mg has been oxidized in the reaction.
The Cl has been present as the diatomic molecule and with the gain of two electrons from the Mg it has been converted to two chloride ions.
Thus, the element that has been reduced in the chemical equation is .
Learn more about reduction, here:
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Answer:
The volume (mL) of 0.135 M NaOH that is required to neutralize 13.7 mL of 0.129 M HCl is 13.1 mL (option b).
Explanation:
The reaction between an acid and a base is called neutralization, forming a salt and water.
Salt is an ionic compound made up of an anion (positively charged ion) from the base and a cation (negatively charged ion) from the acid.
When an acid is neutralized, the amount of base added must equal the amount of acid initially present. This base quantity is said to be the equivalent quantity. In other words, at the equivalence point the stoichiometry of the reaction is exactly fulfilled (there are no limiting or excess reagents), therefore the numbers of moles of both will be in stoichiometric relationship. So:
V acid *M acid = V base *M base
where V represents the volume of solution and M the molar concentration of said solution.
In this case:
- V acid= 13.7 mL= 0.0137 L (being 1,000 mL= 1 L)
- M acid= 0.129 M
- V base= ?
- M base= 0.135 M
Replacing:
0.0137 L* 0.129 M= V base* 0.135 M
Solving:
V base=0.0131 L = 13.1 mL
<u><em> The volume (mL) of 0.135 M NaOH that is required to neutralize 13.7 mL of 0.129 M HCl is 13.1 mL (option b).</em></u>