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3 years ago

What is the ph of a 0.010 m triethanolammonium chloride, (hoc2h2)3nhcl, solution?

Chemistry

1 answer:

azamat3 years ago

8 0

The answer is 4.89

The explanation:

when the Kb of ((HOC2H2)3N) = 5.9 x 10^-7

1- we can get the value of Ka from Kb:

when Ka = Kw / Kb

= 1 x 10^-14 / 5.9 x 10^-7

= 1.69 x 10^-8

2- now we will calculate the [H+] value:

when [H+] = √(Ka*[HA])

=√((1.69E-8)(0.010))

= 1.3 x 10^-5 M

3- the final step we will calculate the PH value from the value of [H+]:

PH = - ㏒ [H+]

= - ㏒ 1.3 x 10^-5

= 4.89

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Is glass breaking physical or a chemical

serg [7]

Answer:

<h2>physical </h2>

Explanation:

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3 0

3 years ago

When 61.6 g of alanine (C3H7NO2) are dissolved in 1150. g of a certain mystery liquid X, the freezing point of the solution is 2

MrRissso [65]

Answer:

Explanation:

From the given information:

TO start with the molarity of the solution:

$= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ C_3H_7 NO_3}{89.1 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}$

= 0.601 mol/kg

= 0.601 m

At the freezing point, the depression of the solution is $\Delta \ T_f = T_{solvent}- T_{solution}$

$\Delta \ T_f = 2.9 ^0 \ C$

Using the depression in freezing point, the molar depression constant of the solvent $K_f = \dfrac{\Delta T_f}{m}$

$K_f = \dfrac{2.9 ^0 \ C}{0.601 \ m}$

$K_f = 4.82 ^0 C / m}$

The freezing point of the solution $\Delta T_f = T_{solvent} - T_{solution}$

$\Delta T_f = 7.3^ 0 \ C$

The molality of the solution is:

$= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ NH_4Cl}{53.5 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}$

Molar depression constant of solvent X, $K_f = 4.82 ^0 \ C/m$

Hence, using the elevation in boiling point;

the Vant'Hoff factor $i = \dfrac{\Delta T_f}{k_f \times m}$

$i = \dfrac{7.3 \ ^0 \ C}{4.82 ^0 \ C/m \times 1.00 \ m}$

$\mathbf {i = 1.51 }$

3 0

2 years ago

7. Suppose each of these isotopes emits a beta particle. Give the iso-

Volgvan

In a beta emission, the mass number of the daughter nucleus remains unchanged while the atomic number of the daughter nucleus increases by one unit. The following are isotopes produced when the following undergo beta emission;

1) potassium-42 ------> Ca - 42

2) iodine-131 ------------> Xe - 131

3) iron-52 ---------------> Co - 52

4) sodium-24 -----------> Mg -24

The daughter nucleus formed after beta emission is found one place after its parent in the periodic table.

Regarding the stability of the daughter nuclei, a nucleus is unstable if the neutron-proton ratio is less than 1 or greater than 1.5.

Hence, the following daughter nuclei are stable; Ca - 42, Xe - 131, Mg -24.

Learn more: brainly.com/question/1371390

7 0

2 years ago

Magnesium hydroxide is added to a solution of hydrochloric acid. A reaction occurs and magnesium chloride and water are formed.

kodGreya [7K]

Answer:Magnesium (Mg) is a - reactant

Hydrogen (H2) is a - product

magnesium chloride (MgCI2) is a - product

hydrochloric acid (HCI) is a - reactant

Explanation: It’s in my notes

8 0

2 years ago

Calculate how much heat is absorbed by a sample that weighs 12 kilograms, has a specific heat of 0.231 kg/CJ, and is heated from

Andrei [34K]

Answer:

97 J

Explanation:

Step 1: Given data

Mass of the sample (m): 12 kg

Specific heat capacity (c): 0.231 J/kg.°C (this can also be expressed as 0.231 J/kg.K)

Initial temperature: 45 K

Final temperature: 80 K

Step 2: Calculate the temperature change

ΔT = 80 K - 45 K = 35 K

Step 3: Calculate the heat required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.231 J/kg.K × 12 kg × 35 K = 97 J

4 0

2 years ago