Need the image to determine the strength and polarity of the charges in the corners.
using kqq/r^2 and basic geometry to figure out magnitude of electric field at point O
Answer:
kinetic energy than the potential energy it carries
Explanation:
Answer: The molarity of 198 g of barium iodide 
in 2.0 L of solution is 0.253 M.
Explanation:
Given: Mass = 198 g
Volume = 2.0 L
Molarity is the number of moles of solute present in liter of a solution.
Moles is the mass of a substance divided by its molar mass. So, moles of barium iodide (molar mass = 391.136 g/mol) is calculated as follows.
Now, molarity is calculated as follows.
Thus, we can conclude that the molarity of 198 g of barium iodide in 2.0 L of solution is 0.253 M.
Answer:
1.84 × 10⁻³
Explanation:
Step 1: Write the balanced equation
2 NOBr(g) ⇄ 2 NO(g) + Br₂(g)
Step 2: Calculate the initial concentration of NOBr
0.143 moles of NOBr(g) are introduced into a 1.00 liter container. The molarity is:
M = 0.143 mol / 1.00 L = 0.143 M
Step 3: Make an ICE chart
2 NOBr(g) ⇄ 2 NO(g) + Br₂(g)
I 0.143 0 0
C -2x +2x +x
E 0.143-2x 2x x
Step 4: Find the value of x
The equilibrium concentration of NOBr(g) was 0.108 M. Then,
0.143-2x = 0.108
x = 0.0175
Step 5: Calculate the concentrations at equilibrium
[NOBr] = 0.108 M
[NO] = 2x = 0.0350 M
[Br₂] = x = 0.0175 M
Step 6: Calculate the equilibrium constant (Kc)
Kc = [0.0350]² × [0.0175] / [0.108]²
Kc = 1.84 × 10⁻³
