Answer:
4.5 moles of H2O.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
C2H5OH + 3O2 —> 2CO2 + 3H2O
From the balanced equation above,
1 moles of C2H5OH reacted to produce 3 moles of H2O.
Finally, we shall determine the number of mole of H2O produced by the reaction of 1.5 moles of C2H5OH. This can be obtained as follow:
From the balanced equation above,
1 moles of C2H5OH reacted to produce 3 moles of H2O.
Therefore, 1.5 moles of C2H5OH will react to produce = 1.5 × 3/ 1 = 4.5 moles of H2O.
Thus, 4.5 moles of H2O will be produced.
Answer:
7.32g of HNO3 are required.
Explanation:
1st) From the balanced reaction we know that 2 moles of HNO3 react with 1 mole of Ca(OH)2 to produce 2 moles of H2O and 1 mole of Ca(NO3)2.
From this, we find that the relation between HNO3 and Ca(OH)2 is that 2 moles of HNO3 react with 1 mole of Ca(OH)2.
2nd) This is the order of the relations that we have to use in the equation to calculate the grams of nitric acid:
• starting with the 4.30 grams of Ca(OH)2.
,
• using the molar mass of Ca(OH)2 (74g/mol).
,
• relation of the 2 moles of HNO3 that react with 1 mole of Ca(OH)2 .
,
• using the molar mass of HNO3 (63.02g/mol).

So, 7.32g of HNO3 are required.
The relation between force and mass and acceleration is

The SI unit will be
Force = Newton
mass =kg
acceleration=
thus

putting values

Thus the acceleration will be
