The most accurately represented John Dalton's model of the atom is: C. a tiny, solid sphere with a predictable mass for a given element
<h3>Further explanation</h3>
The development of atomic theory starts from the first term conveyed by Greek scientists who suggested that every substance has the smallest particles so that the word atomos appears, which means it cannot be divided. So, John Dalton, a British scientist put forward the hypothesis about atoms, among others:
- 1. The elements are composed of atoms which are small particles which cannot be subdivided
- 2. Atoms that make up the same element have the same properties, mass, and size, while for different elements, the properties are also different
- 3. Compounds are composed of two or more atoms in a fixed ratio
- 4. In chemical reactions, atoms after and before a reaction cannot be destroyed, only separation and reassembly occur
Point 3 shows the relationship with The Law of Constant Composition of Proust so that further research on atoms is more developed
Dalton's hypothesis is described as a solid sphere like a very small shot put ball or a bowling ball based on Dalton's hobby in bowling
<h3>Learn more</h3>
Bohr's model of the atom
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Rutherford performed the gold foil experiment
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The part of an atom that is mostly empty space
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Keywords: atom, Dalton, a solid sphere, The Law of Constant Composition
The answer is 6 ft 10 inches in millimeters (mm) is 0.833 ft.
Given,
The center of the school's basketball team is 6 ft 10 inches tall.
We have to convert the height of the player from feet and inches to feet.
Using the conversion factor,
1 ft = 12 inches
or, 12inches/ 1 ft
Converting 6ft 10 inches to ft, we get;
10 inches × 1 ft/ 12inches
= 0.833 ft
Therefore 6 ft 10 inches in millimeters (mm) is 0.833 ft.
Unit conversion is a method in which we multiply or divide with a particular numerical factor and then finally round off to the nearest significant digits.
To learn more about Millimeter and Unit conversions, visit: brainly.com/question/26371870
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Tin metal reacts with hydrogen fluoride to produce tin(II) fluoride and hydrogen gas according to the following balanced equation.
Sn(s)+2HF(g)→SnF2(s)+H2(g)
Sn(s)+2HF(g)→
SnF
2
(s)+
H
2
(g)
How many moles of hydrogen fluoride are required to react completely with 75.0 g of tin?
Step 1: List the known quantities and plan the problem.
Known
given: 75.0 g Sn
molar mass of Sn = 118.69 g/mol
1 mol Sn = 2 mol HF (mole ratio)
Unknown
mol HF
Use the molar mass of Sn to convert the grams of Sn to moles. Then use the mole ratio to convert from mol Sn to mol HF. This will be done in a single two-step calculation.
g Sn → mol Sn → mol HF
Step 2: Solve.
75.0 g Sn×1 mol Sn118.69 g Sn×2 mol HF1 mol Sn=1.26 mol HF
75.0 g Sn×
1
mol Sn
118.69
g Sn
×
2
mol HF
1
mol Sn
=1.26 mol HF
Step 3: Think about your result.
The mass of tin is less than one mole, but the 1:2 ratio means that more than one mole of HF is required for the reaction. The answer has three significant figures because the given mass has three significant figures.
First gap is BY USING MAGNETS
2nd is ELECTROLYSIS
3rd is EVAPORATION
