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Art [367]
3 years ago
10

How much heat is needed to raise the temperature of 8g of water by 15oC?

Physics
1 answer:
Murrr4er [49]3 years ago
5 0
<h2>Answer: 502.08 J</h2>

Explanation:

The heat (thermal energy) needed in to raise the temperature in a process can be found using the following equation:

Q=m.C.\Delta T   (1)

Where:

Q is the heat

m=8 g is the mass of the element (<u>water</u> in this case)

C is the specific heat capacity of the material. In the case of water is C=4.184\frac{J}{g\°C}

\Delta T=15\°C is the variation in temperature  <u>(which is increased in this case)</u>

Knowing this, let's rewrite (1) with these values:

Q=(8 g)(4.184\frac{J}{g\°C})(15\°C)  (2)

Finally:

Q=502.08 J  

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A parallel circuit contains an 18-V battery wired with 2 bulbs with resistances of 8
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Answer:

See below

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7 0
2 years ago
A projectile is fired with an initial speed of 40 m/s at an angle of elevation of 30∘. Find the following: (Assume air resistanc
BabaBlast [244]

Answer:

a. 2.0secs

b. 20.4m

c. 4.0secs

d. 141.2m

e. 40m/s, ∅= -30°

Explanation:

The following Data are giving

Initial speed U=40m/s

angle of elevation,∅=30°

a. the expression for the time to attain the maximum height is expressed as

t=\frac{usin\alpha }{g}

where g is the acceleration due to gravity, and the value is 9.81m/s if we substitute values we arrive at

t=40sin30/9.81\\t=2.0secs

b. the expression for the maximum height is expressed as

H=\frac{u^{2}sin^{2}\alpha  }{2g} \\H=\frac{40^{2}0.25 }{2*9.81} \\H=20.4m

c. The time to hit the ground is the total time of flight which is twice the time to reach the maximum height ,

Hence T=2t

T=2*2.0

T=4.0secs

d. The range of the projectile is expressed as

R=\frac{U^{2}sin2\alpha}{g}\\R=\frac{40^{2}sin60}{9.81}\\R=141.2m

e. The landing speed is the same as the initial projected speed but in opposite direction

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3 0
3 years ago
A4.00-kg box sits on a ramp that is inclined at 30°above the horizontal.The coefficient of kinetic friction between the box and
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From the calculation, we can see that the force that  moves the box forward is 5.7 N.

<h3>What is frictional force?</h3>

The term frictional force refers to the force that opposes motion. Given that;

ma = ukmgcosθ + F

Let F be the forward force.

Hence;

F = ma - ukmgcosθ

F = 4 * 3 - (0.32 * 4.00 * 9.8 * sin 30)

F =  5.7 N

Learn more about frictional force:brainly.com/question/14662717

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