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Mashcka [7]
3 years ago
9

Does changing position of charges change the magnitude

Physics
1 answer:
hodyreva [135]3 years ago
7 0

Answer:

No, they will not change.

Explanation:

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Air is heated in a glass bottle. The heat energy added to the air is 2.0 × 104 joules. What is the change in internal energy of
Liono4ka [1.6K]
The change in internal energy of the gas is \Delta U = 2.0 \cdot 10^4 J.

In fact, the 1st law of thermodynamics states that the change in internal energy of a system is equal to the amount of heat given to the system (Q) plus the work done on the system (W):
\Delta U = Q+W
In this example, no work is done on the bottle so W=0, while the heat given to the system is Q=2.0 \cdot 10^4 J, so the change in internal energy of the gas is
\Delta U = Q = 2.0 \cdot 10^4 J
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What is the importance of discovering gravitational waves in science?
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Light waves are bent more easily than sound waves true or false
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8 0
3 years ago
A student pedaling a bicycle applies a net force of 400 N. The mass of the rider and the bicycle is 25 kg. What is the accelerat
Svetllana [295]

The acceleration is 16 m/s^2

Explanation:

We can answer this question by using Newton's second law, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:

F=ma

where

F is the force

m is the mass

a is the acceleration

In this problem, we have

m = 25 kg is the mass of the rider+bicycle

F = 400 N is the force

Solving for a, we find the acceleration:

a=\frac{F}{m}=\frac{400}{25}=16 m/s^2

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

6 0
4 years ago
Read 2 more answers
Write the differential equation that governs the motion of the damped mass-spring system, and find the solution that satisfies t
melisa1 [442]

This question is incomplete, the complete question  is;

Write the differential equation that governs the motion of the damped mass-spring system, and find the solution that satisfies the initial conditions specified. Units are mks; γ is the damping coefficient, with units of kg/sec

m = 0.2, γ = 1.6 and k = 4

Initial displacement is 1 and initial velocity is -2

x" + _____ x' ____x = 0

x(t) =

Answer:

the solution that satisfies the initial conditions specified is;

x(t) = c_1e^{-4t}cos(2t) + c_2e^{-4t}sin(2t)

Explanation:

Given the data in the question ;

m = 0.2, γ = 1.6, k = 4

x(0) = 1, x'(0) = -2

Now, the differential equation that governs the motions of spring mass system is;

mx" + γx' + kx = 0

so we substitute

0.2x" + 1.6x' + 4x = 0

divide through by 0.2

x" + 8x' + 20x = 0

hence, characteristics equation will be;

m² + 8m + 20 = 0

we find m using; x = [ -b±√(b² - 4ac) ] / 2a

m = [ -8 ± √((8)² - 4(1 × 20 )) ] / 2(1)

m = [ -8 ± √( 64 - 80 ) ] / 2

m = [ -8 ± √-16 ) ] / 2

m = ( -8 ± 4i ) / 2

m = -4 ± 2i

Hence, the general solution of the differential equation is;

x(t) = c_1e^{-4t}cos(2t) + c_2e^{-4t}sin(2t)

From the initial conditions;

c₁ = 1, c₂ = 1

the solution that satisfies the initial conditions specified is;

x(t) = c_1e^{-4t}cos(2t) + c_2e^{-4t}sin(2t)

6 0
3 years ago
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