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BigorU [14]
2 years ago
9

Prove: 1) p=dhg .........​

Physics
1 answer:
Lilit [14]2 years ago
6 0

Explanation:

P = F/A

P = mg/A [ since F = mg ]

P = Vdg/A [ since m = Vd ]

P = Ahdg/A [ since V = Ah ]

P = hdg

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Wave traveling at 330 m/sec has a wavelength of 4.3 meters. What is the frequency of this wave?
Rasek [7]

Answer:

76.74 Hz

Explanation:

Given:

Wave velocity ( v ) = 330 m / sec

wavelength ( λ ) = 4.3 m

We have to calculate Frequency ( f ):

We know:

v = λ / t [ f = 1 / t ]

v = λ f

= > f = v / λ

Putting values here we get:

= > f = 330 / 4.3 Hz

= > f = 3300 / 43 Hz

= > f = 76.74 Hz

Hence, frequency of sound is 76.74 Hz.

6 0
2 years ago
On a color wheel, colors that are directly across from each other are called _______ colors.
Salsk061 [2.6K]
I believe the answer is : A
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3 years ago
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Answer:

       

Explanation:

       

3 0
2 years ago
a baseball is hit 3 feet above ground level at 100 feet per second and at an angle of 45 with respect to the ground. (g=32 feet/
LiRa [457]

Answer:

hmax=81ft

Explanation:

Maximum height of the object is the highest vertical position along its trajectory.

The vertical velocity is equal to 0 (Vy = 0)

0=V_{y}-g*t=v_{0}*sin(\alpha)-g*th\\

we isolate th (needed to reach the maximum height hmax)

th = \frac{v_{0}*sin(\alpha)}{g}

The formula describing vertical distance is:

y = Vy * t-g* t^{2} / 2

So, given y = hmax and t = th, we can join those two equations together:

hmax = Vy* th-g*th^{2}/2

hmax =Vo^{2}*sin(\alpha )^{2}/(2*g)

if we launch a projectile from some initial height h all you need to do is add this initial elevation

hmax =h+Vo^{2}*sin(\alpha)^{2}/(2*g)

hmax =3+100^{2}*sin(45)^{2}/(2 * 32)=81 ft

6 0
3 years ago
The half of the moon facing the sun is always lit, but the different phases happen
Marizza181 [45]

Answer:

the answer is the spinning of the moon lets us see different amounts of light

Explanation:

you wanna know why uh yes ok lets cut to the magic so when the moon.

3 0
3 years ago
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