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12345 [234]
3 years ago
5

When the tympanic membrane vibrates with the same frequency as the incoming sound waves it is known asamplitude.pitch.hertz.reso

nance.cycles.
Physics
1 answer:
Sphinxa [80]3 years ago
4 0
<h2>Answer: Resonance </h2>

Resonance is a phenomenon that occurs when a body capable of vibrating is subjected to the action of a periodic force, whose frequency of vibration approaches the characteristic frequency of vibration (called resonance frequence) of said body. This is due a relatively small force applied in a repeated form, causing the amplitude of the oscillating system to become very large.

In other words, for the specific case of sound waves, this phenomenon occurs when the frequency of the  wave that is external to the system or body coincides with the resonance frequency (characteristic frequency that reaches the maximum degree of oscillation) of this system or body.

In these circumstances the body vibrates, progressively increasing the amplitude of movement after each successive actions of the force. However, this effect can be destructive in some rigid materials.

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If a body is accelerating m change the velocity of 2 metre per second square when it was acted by five hundred Newton of force t
WARRIOR [948]
  • Force=500N
  • Acceleration=2m/s^2

using newtons law

\\ \rm\Rrightarrow Force=Mass(Acceleration)

\\ \rm\Rrightarrow Mass=\dfrac{Force}{Acceleration}

\\ \rm\Rrightarrow Mass=\dfrac{500}{2}

\\ \rm\Rrightarrow Mass=250kg

5 0
2 years ago
Read 2 more answers
A policeman starts giving chase 60 seconds after a stolen car zooms by at 108 km/hr. At what minimum speed should he drive if he
Iteru [2.4K]

Answer:

30.93 m/s

Explanation:

Given that, the speed of stolen car is,

v_{s} =108km/hr\\v_{s} =108\times \frac{5}{18}m/s\\ v_{s} =30m/s

As policeman start chasing the stolen car after 60 seconds.

Now suppose the speed of policeman car is, v_{p}

The policeman catches the stolen car at a distance of,

S=60km\\S=60000m

Now the distance covered by the policeman in time t is v_{p}\times t

And the distane cover by the thief in stolen car in time(t+60s) is v_{s}\times (t+60sec).

And these distances are equal and they are equal to 60000 m.

Therefore,

v_{p}\times t=v_{s}\times (t+60sec)=60000m

Therfore,

v_{s}\times (t+60sec)=60000m\\30m/s\times (t+60sec)=60000m\\(t+60s)=2000s\\t=1940s

Now use this value to solve for minimum speed of policeman's car.

v_{p}\times 1940=60000\\v_{p}=30.93 m/s

Therefore minimum speed of policeman's car is 30.93 m/s.

6 0
3 years ago
A transverse wave on a rope is given by y(x,t)= (0.750cm)cos(π[(0.400cm−1)x+(250s−1)t]). part a part complete find the amplitude
Pani-rosa [81]
The amplitude of a wave corresponds to its maximum oscillation of the wave itself. 
In our problem, the equation of the wave is
y(x,t)= (0.750cm)cos(\pi [(0.400cm-1)x+(250s-1)t])
We can see that the maximum value of y(x,t) is reached when the cosine is equal to 1. When this condition occurs,
y(x,t)=0.750 cm
and therefore this value corresponds to the amplitude of the wave.
4 0
3 years ago
Read 2 more answers
If you drag a 50kg block across the floor which has a coefficient of friction of .30, what is
torisob [31]

Answer:

750 Newton

Explanation:

force=mass(acceleration)

6 0
2 years ago
Problem 21-40a:
Greeley [361]

Answer:

Part a)

\frac{F_e}{F_g} = 2.74 \times 10^{12}

Part b)

q = 3.37 \times 10^{-4} C

Explanation:

As we know that electric force on electric charge is given as

F = qE

here we have

q = 1.6 \times 10^{-19}C

E = 153 N/C

now force is given as

F = (1.6 \times 10^{-19})(153) = 2.45 \times 10^{-17} N

Gravitational force on electric charge near surface of earth is given as

F_g = mg

F_g = (9.1 \times 10^{-31})(9.81) = 8.93 \times 10^[-30} N

now the ratio of two forces is given as

\frac{F_e}{F_g} = \frac{2.45 \times 10^{-17}}{8.93 \times 10^{-30}}

\frac{F_e}{F_g} = 2.74 \times 10^{12}

Part b)

Now the ball is balanced by the electric force and the force of gravity on it

so here we have

F_g = qE

mg = qE

(5.25 \times 10^{-3})(9.81) = q(153)

here we have

q = 3.37 \times 10^{-4} C

8 0
3 years ago
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