Step-by-step explanation:
By question ,
=> cot∅ = 2/11
=> cot∅ = 2x/11x = b/p
<u>Pyhthagoras</u><u> Theorem</u><u> </u><u>:</u><u>-</u><u> </u>
=> h² = (2x)² + (11x)²
=> h² = 4x² + 121x²
=> h² = 125x²
=> h = √ 25 × 5 x
=> h = 5√5 x
- Sin∅ = 11/5√5
- cosec∅ = 5√5/11
- cos∅ =2/5√5
- tan∅ = 11/2
- sec∅ = 5√5/2
The integers are 68 and 70.
One half of 68 is 34.
One fifth of 70 is 14.
34 + 14 = 48 and 68 and 70 are consecutive even integers.
-4(2y)+11y=15
-8y+11y=15
3y=15
y=5
-4x+11(5)=15
-4x+55=15
-4x= -40
x=10
Step-by-step explanation:
19 = -23+ 6(2 - p)
19=-23+12-6p
19=-11-6p
6p=-11-19
6p=-30
p= -5