Answer:
power = 384.92 W
Explanation:
given data
resistance = 44.0 Ω
impedance = 71 Ω
ΔVrms = 210 V
to find out
average power
solution
we know here power formula that is
power = cos∅ .........1
we know here cos∅ =
cos ∅ = = 0.6197
so from equation 1
power = × 0.6197
power = 384.92 W
Answer:
0.0268 m
Explanation:
Draw a free body diagram of the block. There are three forces: weight force mg pulling down, buoyancy of the oil B₁ pushing up, and buoyancy of the water B₂ pushing up.
Sum of forces in the y direction:
∑F = ma
B₁ + B₂ − mg = 0
ρ₁V₁g + ρ₂V₂g − mg = 0
ρ₁V₁ + ρ₂V₂ = m
ρ₁V₁ + ρ₂V₂ = ρV
ρ₁Ah₁ + ρ₂Ah₂ = ρAh
ρ₁h₁ + ρ₂h₂ = ρh
(930 kg/m³)h₁ + (1000 kg/m³)h₂ = (968 kg/m³) (4.93 cm)
Since the block is fully submerged, h₁ + h₂ = 4.93 cm.
(930 kg/m³) (4.93 cm − h₂) + (1000 kg/m³)h₂ = (968 kg/m³) (4.93 cm)
h₂ = 2.68 cm
h₂ = 0.0268 m
Its called compressing the gas
Answer:
First Car Avg: Velocity=0.11 m/s
Second Car Avg: Velocity=0.28 m/s
Explanation:
Data
D1 (First Car Displacement)=0.25m
T1 (First Car total time taken)=2.23s
D2 (Second Car Displacement)=0.25m
T2(Second Car time taken)=3.13-2.23=0.9s
Avg: Velocity1=?
Avg: Velocity2=?
Solution
Avg: Velocity1=D1/T1
Avg: Velocity1=0.25/2.23
Avg: Velocity1=0.11 m/s
Avg: Velocity2=D2/T2
Avg: Velocity2=0.25/0.9
Avg: Velocity2=0.28 m/s
Given
m1(mass of red bumper): 225 Kg
m2 (mass of blue bumper): 180 Kg
m3(mass of green bumper):150 Kg
v1 (velocity of red bumper): 3.0 m/s
v2 (final velocity of the combined bumpers): ?
The law of conservation of momentum states that when two bodies collide with each other, the momentum of the two bodies before the collision is equal to the momentum after the collision. This can be mathemetaically represented as below:
Pa= Pb
Where Pa is the momentum before collision and Pb is the momentum after collision.
Now applying this law for the above problem we get
Momentum before collision= momentum after collision.
Momentum before collision = (m1+m2) x v1 =(225+180)x 3 = 1215 Kgm/s
Momentum after collision = (m1+m2+m3) x v2 =(225+180+150)x v2
=555v2
Now we know that Momentum before collision= momentum after collision.
Hence we get
1215 = 555 v2
v2 = 2.188 m/s
Hence the velocity of the combined bumper cars is 2.188 m/s