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vagabundo [1.1K]
3 years ago
14

A series RLC circuit has a resistance of 44.0 Ω and an impedance of 71.0 Ω. What average power is delivered to this circuit when

ΔVrms = 210 V?
Physics
1 answer:
blagie [28]3 years ago
6 0

Answer:

power = 384.92 W

Explanation:

given data

resistance = 44.0 Ω

impedance = 71 Ω

ΔVrms = 210 V

to find out

average power

solution

we know here power formula that is

power =  \frac{V^2rms}{impedance}cos∅ .........1

we know here cos∅  =  \frac{resistance}{impedance}

cos ∅  =  \frac{44}{71} = 0.6197

so from equation 1

power =  \frac{210^2}{71} × 0.6197

power = 384.92 W

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<u>                                                                                                                                 </u>

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