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timofeeve [1]
2 years ago
9

Use the passage to answer the question.

Physics
1 answer:
Studentka2010 [4]2 years ago
3 0

This is not something that waves do because they need a medium to travel through, while particles do not.

<h3>How light travels in space?</h3>

A light travels without any medium while on the other hand, a medium is required for sound waves to move from oe place to another. Sound is a mechanical wave that cannot travel through a vacuum.

So we can conclude that electromagnetic waves like light do not require medium for its propagation.

Learn more about light here: brainly.com/question/19697218

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a vertical polarizing filter is used on the lens of a camera. Which of the following do not strike the lens?
ziro4ka [17]
A vertical polarizing filter is used on the lens of a camera,  they block out the light that is horizontally polarized, so they allow all of the vertically polarized<span> light to pass through.</span>
8 0
3 years ago
If two different theories describe experimental observations equally well, can one be said to be more valid than the other (assu
Andreas93 [3]

Answer:

No

Explanation:

In such situations we cannot determine which one is more valid as both serves the purpose well.

Two theories are carried out in different environment and circumstance keeping different parameters and one can opt for any number of ways to carry out that experiment but what matter at the end is the accuracy they bring.

Each of the theory is a new discovery and follows all the possible logical rules hence it is not possible to decide which one is more valid.

3 0
3 years ago
You calculate the density of a block of aluminum to be 2.68 g/cm3. You look up the density of a block of aluminum at room temper
Hunter-Best [27]

Answer:

Systematic errors.

Explanation:

The density of the aluminium was calculated by a human and this is not natural but can be due to errors in the calibration of the scale for measuring the weight or taking readings from the measuring cylinder.

Random errors are natural errors. Random errors in experimental measurements are caused by unknown and unpredictable changes in the experiment. Systematic errors are due to imprecision or problems with instruments.

3 0
3 years ago
Which situations contain unbalanced forces? Check all that apply.
coldgirl [10]

A book falls to the floor.

A car skids to a stop.

A foam ball launches from a spring (Are the right answer, just did this one 4:34 pm Jan/21/19)

8 0
3 years ago
Read 2 more answers
Air enters a turbine operating at steady state at 8 bar, 1600 K and expands to 0.8 bar. The turbine is well insulated, and kinet
kobusy [5.1K]

Answer:

the maximum theoretical work that could be developed by the turbine is 775.140kJ/kg

Explanation:

To solve this problem it is necessary to apply the concepts related to the adiabatic process that relate the temperature and pressure variables

Mathematically this can be determined as

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^{(\frac{\gamma-1}{\gamma})}

Where

Temperature at inlet of turbine

Temperature at exit of turbine

Pressure at exit of turbine

Pressure at exit of turbine

The steady flow Energy equation for an open system is given as follows:

m_i = m_0 = mm(h_i+\frac{V_i^2}{2}+gZ_i)+Q = m(h_0+\frac{V_0^2}{2}+gZ_0)+W

Where,

m = mass

m(i) = mass at inlet

m(o)= Mass at outlet

h(i)= Enthalpy at inlet

h(o)= Enthalpy at outlet

W = Work done

Q = Heat transferred

v(i) = Velocity at inlet

v(o)= Velocity at outlet

Z(i)= Height at inlet

Z(o)= Height at outlet

For the insulated system with neglecting kinetic and potential energy effects

h_i = h_0 + WW = h_i -h_0

Using the relation T-P we can find the final temperature:

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^{(\frac{\gamma-1}{\gamma})}\\

\frac{T_2}{1600K} = (\frac{0.8bar}{8nar})^{(\frac{1.4-1}{1.4})}\\ = 828.716K

From this point we can find the work done using the value of the specific heat of the air that is 1,005kJ / kgK

W = h_i -h_0W = C_p (T_1-T_2)W = 1.005(1600 - 828.716)W = 775.140kJ/Kg

the maximum theoretical work that could be developed by the turbine is 775.140kJ/kg

4 0
3 years ago
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