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rewona [7]
3 years ago
8

Plz help me to find my science matching... ​

Physics
1 answer:
s2008m [1.1K]3 years ago
5 0

Answer:

fibrous =potato

taproot =radish

stilt =maize and sugar cane

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After the driver first notices the obstacle, the car moves uniformly for a time interval t1−t0=t before the brakes are applied.
loris [4]

Answer:

V(t1-t0)

Explanation:

Moving 'uniformly' means constant velocity (speed). the formula for constant speed motion is V = \frac{distance}{time} =( change in position/ change in time)

where,

                  V is speed

given in the statement :

change in time = t =  t1-t0

let the constant speed be ' V '

disance = X = X1-X0

applying the above mentioned formula: V = \frac{X}{t}

V = X/t

X = Vt

the distance X1-X0 = Vt =V(t1-t0)

3 0
3 years ago
I NEED PHYSICS HELP ASAP! DO NOT GUESS! I WILL GIE BRAINLEIST IF RIGHT! THANKS! :D
ale4655 [162]
<span>The repelling of the support magnet decreases friction. is the answer you're looking for .  :)

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6 0
3 years ago
Read 2 more answers
The resistance of the body varies from approximately 500 kΩ (when it is very dry) to about 1.00kΩ (when it is wet). The maximum
Nady [450]

Answer:

you absolute buffoon Use Ohms' Law:   V = RI

V = (1x10^3)(5x10^-3) = 5 volts

Yes, this is in the range of normal household voltages.  

Explanation:

4 0
3 years ago
Which statements about electric field lines are correct? Check all that apply.
slava [35]

Answer:

they cross over one another between charge.

7 0
3 years ago
A hot cube of iron was heated up using 1500 J of thermal energy and was placed in a beaker of water. Before it was heated, the i
Mariana [72]

Answer:

451.13 J/kg.°C

Explanation:

Applying,

Q = cm(t₂-t₁)............... Equation 1

Where Q = Heat, c = specific heat capacity of iron, m = mass of iron, t₂= Final temperature, t₁ = initial temperature.

Make c the subject of the equation

c = Q/m(t₂-t₁).............. Equation 2

From the question,

Given: Q = 1500 J, m = 133 g = 0.113 kg, t₁ = 20 °C, t₂ = 45 °C

Substitute these values into equation 2

c = 1500/[0.133(45-20)]

c = 1500/(0.133×25)

c = 1500/3.325

c = 451.13 J/kg.°C

4 0
3 years ago
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