Plz help me to find my science matching... <br>

Collisions between atoms are often elastic, but sometimes inelastic collisions occur, and the lost kinetic energy can become int

Galina-37 [17]

Answer:

a) E = 6.4 1019 J b) v = 0.69 10⁴4 m / s

Explication

a) convert E = 4.0 eV

1 eV = 1.6 10⁻¹⁹ J

E = 4.0 eV (1.6 10⁻¹⁹ J / 1 eV)

E = 6.4 10⁻¹⁹ J

b) Suppose we have a frontal shock and all the kinetic energy of oxygen is transferred to Cs

Ei = K = ½ m v²

Ef = 6.4 10⁻¹⁹ J

½ m v² = 6.4 10⁻¹⁹

The oxygen mass of the periodic table is

PA = 15,999 u

1u = 1.660 10⁻²⁷ kg

Pa = 15,999 1,660 10⁻²⁷ kg

m= Pa = 26,558 10⁻²⁷ kg

Let's calculate the speed

v2 = 2 / m 6.4 10⁻¹⁹

v2 = 2 / 26,558 10⁻²⁷ 6.4 10⁻¹⁹ =

v = √0.4819 10⁸

v = 0.69 10⁴4 m / s

4 0

3 years ago

After watching a show about submarines, Jamil wants to learn more about the oceans. Which question could be answered through sci

krok68 [10]

Answer:

After watching a show about submarines, Jamil wants to learn more about the oceans. The question that could be answered through scientific investigation is What substances dissolve in ocean water?

<u>Explanation:</u>

Jamil's scientific investigation will help him learn about the various substances that can be dissolved in seawater. There is a large number of such substances. Salt is the most important component of seawater.

Sodium chloride is the most common substance. Besides it, magnesium chloride and calcium chloride are also dissolved in seawater. Seawater consists of a large number of gases also such as oxygen, nitrogen, carbon dioxide, etc.

4 0

3 years ago

Read 2 more answers

Why should you explore the potential roadblocks to your chosen career?

valina [46]

Answer: D

Explanation: D is the most reasonable answer because it's always good to plan ahead for anything, so if you were to plan ahead for future obstacles, then you can overcome them.

6 0

3 years ago

A shark is cruising at 4 m/s when it sees a fish straight

Oksanka [162]

Answer:

Distance, S = 13m

Explanation:

Given the following data;

Initial velocity, u = 4m/s

Final velocity, v = 9m/s

Time, t = 2 seconds

To find the distance, S;

First of all, we would determine the acceleration of the shark.

Acceleration = (v - u)/t

Acceleration = (9 - 4)/2

Acceleration = 5/2

Acceleration = 2.5m/s²

Now, to find the distance we would use the second equation of motion

S = ut + ½at²

Substituting into the equation, we have

S = 4(2) + ½*2.5*2²

S = 8 + 1.25*4

S = 8 + 5

Distance, S = 13m

3 0

3 years ago

A 782-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satelli

Vadim26 [7]

Answer:

a) v = 5.59x10³ m/s

b) T = 4 h

c) F = 1.92x10³ N

Explanation:

a) We can find the satellite's orbital speed by equating the centripetal force and the gravitation force as follows:

$F_{c} = F_{G}$

$\frac{mv^{2}}{r + h} = \frac{GMm}{(r + h)^{2}}$

$v = \sqrt{\frac{gr^{2}}{r+h}$

Where:

g is the gravity = 9.81 m/s²

r: is the Earth's radius = 6371 km

h: is the satellite's height = r = 6371 km

$v = \sqrt{\frac{gr^{2}}{2r}} = \sqrt{\frac{gr}{2}} = \sqrt{\frac{9.81 m/s^{2}*6.371 \cdot 10^{6} m}{2}} = 5.59 \cdot 10^{3} m/s$

b) The period of its revolution is:

$T = \frac{2\pi}{\omega} = \frac{2\pi (r + h)}{v} = \frac{2\pi (2*6.371 \cdot 10^{6} m)}{5.59 \cdot 10^{3} m/s} = 14322.07 s = 4 h$

c) The gravitational force acting on it is given by:

$F = \frac{GMm}{(r + h)^{2}}$

Where:

M is the Earth's mass = 5.97x10²⁴ kg

m is the satellite's mass = 782 kg

G is the gravitational constant = 6.67x10⁻¹¹ Nm²kg⁻²

$F = \frac{GMm}{(r + h)^{2}} = \frac{6.67 \cdot 10^{-11} Nm^{2}kg^{-2}*5.97 \cdot 10^{24} kg*782 kg}{(2*6.371 \cdot 10^{6} m)^{2}} = 1.92 \cdot 10^{3} N$

I hope it helps you!

3 0

3 years ago

Plz help me to find my science matching... ​

Plz help me to find my science matching...