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4 years ago

The amount of kinetic energy an object has can And is related to the objects And.

1 answer:

7 0

he kinetic energy of an object is the energy it has because of its motion. In Newtonian (classical) mechanics, which describes macroscopic objects moving at a small fraction of the speed of light, the kinetic energy ( E) of a massive body in motion can be calculated as half its mass ( m) times the square of its velocity.

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Two balls have the same mass of 5.00 kg. Suppose that these two balls are attached to a rigid massless rod of length 2L, where L

olga_2 [115]

Answer:

Explanation:

Given

mass of balls $m= 5 kg$

$N=45.6 rev/s$

angular velocity $\omega =2\pi N=286.55 rad/s$

Length of Rod $2L=1.1 m$

Tension in the Second half of rod

$T_2=m\omega ^2(2L)=2m\omega ^2L$

$T_2=5\times (286.55)^2\times 1.1$

$T_2=451.609 kN$

For First Part

$T_1-T_2=m\omega ^2L$

$T_1=T_2+m\omega ^2L$

$T_1=3 m\omega ^2L$

$T_1=3\times 5\times (286.55)^2\times 0.55$

$T_1=677.41 kN$

7 0

3 years ago

An objects momentum is determined by the object's

n200080 [17]

~Hello there! ^_^

Your question: An objects momentum is determined by the object's..?

Your answer: An objects momentum is determined by the object's mass and velocity.

Happy Studying! =)

7 0

4 years ago

Strontium chloride, SrCl2<br> Is ionic or covalent

Cloud [144]

Answer:

it is a ionic bond because electrons are transferred from chlorine to strontium

5 0

3 years ago

Read 2 more answers

An object with charge q = −6.00×10−9 C is placed in a region of uniform electric field and is released from rest at point A. Aft

Arte-miy333 [17]

Answer:

The electric potential at point B is 83.33 V

The magnitude of the electric field at point B is 166.67 N/C

Explanation:

Given;

charge of an object, q = −6.00×10⁻⁹ C

Kinetic energy = 5.00×10⁻⁷ J

Electric potential at point A = +30.0 V

To determine the electric potential at point B, we apply the following formula;

Fd = qEd

Also, Fd is work done in moving the charge to 0.5 m = K.E

Again, Ed is the electric potential at point B (VB)

Substitute for V and K.E in the above equation, we will have;

K.E = q(VB)

VB = K.E/q

$V_B = \frac{5*10^{-7}}{6*10^{-9}} = 83.33 \ V_B$

To determine the magnitude of the electric field at B, we use equation below;

V = Ed

$E = \frac{V}{d} = \frac{83.33}{0.5} = 166.67 \ N/C$

3 0

3 years ago

Differentiate between Physical and chemical changes with example<br>please help me ! <br>

Anna11 [10]

Answer:

<em>Physical change is a temporary change. A chemical change is a permanent change</em>

<em>examples of physical change are freezing of water, melting of wax, boiling of water, etc. A few examples of chemical change are digestion of food, burning of coal, rusting, etc.</em>

HAVE A GREAT DAY :)

3 0

3 years ago