Answer:
1) p₀ = 45000 N / s
, p₀ '= 1800
, b) I = -45000 N s
, I = 1800 Ns
Explanation:
Impulse equals the change in momentum
I = Δp
1) the initial moment of the car
p₀ = M v
p₀ = 1500 30
p₀ = 45000 N / s
the change at the moment is
Δp = 45000
because the end the car is stopped
moment of the person
P₀ ’= m v
p₀ '= 60 30
p₀ '= 1800
D₀ '= 1800
2) of the momentum change impulse ratio
car
I = Δp
I = -45000 N s
person
I = Δpo '
I = 1800 Ns
3) the object that give the momentum to stop the wall motoring
The person is stopped by the impulse given by the car
a) This area is the one that absorbs most of the vehicle impulse
be) If using a safety painter, the time during which the greater force will act, therefore the lessons decrease
c) The air bag helps reduction in the speed of the person relatively quickly.
Answer:
Explanation:
I guess we are ASSUMING that this is a rear wheel drive car as a front wheel drive car will never get the front wheel normal force to zero
If we consider it as a statics problem and choose our moment center carefully...say 0.7 m above the rear wheel to ground contact point.
Call the traction force at the rear wheels F
The normal force on the front wheels will be zero, so no moment generated by the front wheels.
Summing moments about our chosen point to zero
1600(9.8)[2.6 / 2] - F[0.7] = 0
F = 291,200
this force will create an acceleration of
a = F/m
a = 291200/1600
a = 182 m/s²
which is about 18.6 times gravity acceleration
Answer:
That happens to me a few times.
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Answer:
2H₂S + SO₂ —> 2H₂O + 3S
Explanation:
From the question given above, the following equation were obtained:
H₂S + SO₂ —> H₂O + S
The equation can be balance as illustrated below:
H₂S + SO₂ —> H₂O + S
There are 2 atoms of O on the left side and 1 atom on the right side it can be balance by writing 2 before H₂O as shown below:
H₂S + SO₂ —> 2H₂O + S
There are 2 atoms of H on the left side and 4 atoms on the right side. It can be balance by writing 2 before H₂S as shown below:
2H₂S + SO₂ —> 2H₂O + S
There are 3 atoms of S on the left side and 1 atom on the right side. It can be balance by writing 3 before S as shown below:
2H₂S + SO₂ —> 2H₂O + 3S
Now, the equation is balanced.!
