Dry, white powder, soluble in water to form a slightly basic solution
14.5 M
Molarity=grams/liters
M=58/4.0
Conformity can be inappropriate when you’re confirming to do negotiate things. Example smoke cigs
Phosphoric acid has 3 pKa values (pKa1=2.1, pKa2=6.9, pKa3= 12.4) and after 3 ionization it gives 3 types of ions at different pKa values:
H₃PO₄(aq) + H₂O(l) ⇌ H₃O⁺(aq) + H₂PO₄⁻ (aq) pKₐ₁
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</span>H₂PO₄⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HPO₄²⁻ (aq) pKₐ₂
HPO₄²⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + PO₄³⁻ (aq) pKₐ₃
The last equilibrium is associated with the highest pKa value (12.4) of phosphoric acid. There the last OH group will lose its hydrogen and hydrogen phosphate ion (HPO₄²⁻) turns into phosphate ion (PO₄³⁻).
Answer:
11.54 M
Explanation:
In this case, all we have to do is to apply the following expression:
M = n/V
M: molarity
n: moles
V: volume of solution in liters
In this case, we can assume that the volume of water will be the volume of solution. This is because the problem is not specifing if the moles of AgNO3 are liquid or solid, so we can make a safe assumption of the volume.
Using the expression above we have:
M = 5.54 / 0.48
M = 11.54 M
This is the molarity of solution
