How many moles of a gas sample are in a 10.0 L container at 373 K and 203 kPa? the gas constant is 8.31 L -kPa/ mol-K.
2 answers:
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<u>Answer:</u> The concentration of required will be 0.285 M.
<u>Explanation:</u>
To calculate the molarity of , we use the equation:
Moles of = 0.016 moles
Volume of solution = 1 L
Putting values in above equation, we get:
For the given chemical equations:
Net equation:
To calculate the equilibrium constant, K for above equation, we get:
The expression for equilibrium constant of above equation is:
As, is a solid, so its activity is taken as 1 and so for
We are given:
Putting values in above equations, we get:
Hence, the concentration of required will be 0.285 M.