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harkovskaia [24]
3 years ago
10

Calculate the normality of a solution containing 147 g of h2s04 in 2L of solution

Chemistry
1 answer:
babunello [35]3 years ago
5 0
I am not sure plz show me the question
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I am a teacher in a college in a large city in China. One day, some students asked me to join
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c or b

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the story is entertaining and it shares the teachers personal experiences with the teachers students

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When sound molecules "stack up" in front of high-speed flights, what could
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What is the correct formula name for calcium chloride?
Leokris [45]
C. CaCl2 is the correct answer
7 0
3 years ago
NH3 + HCl---> NH4Cl What is the Chemical reaction
KATRIN_1 [288]

Answer:

A combination reaction

Explanation:

The chemical reaction between ammonia and hydrochloric acid as shown below:

         NH₃  +  HCl →  NH₄Cl

is a combination reaction.

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A combination reaction is also known as a synthesis reaction.

A single product forms from tow or more reactants.

The driving force for such reaction is the large and negative heat of formation of the product.

5 0
3 years ago
2KMnO4= K2MnO4+ MnO2+O2 how many grams of KMnO4 are required to produce 1.60 grams of O2
Sergeu [11.5K]

Answer: 15.8 g of KMnO_4 will be required to produce 1.60 grams of O_2

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} O_2=\frac{1.60g}{32g/mol}=0.05moles

2KMnO_4\rightarrow K_2MnO_4+MnO_2+O_2

According to stoichiometry :

As 1 mole of O_2 is given by = 2 moles of KMnO_4

Thus 0.05 moles of O_2 is given by =\frac{2}{1}\times 0.05=0.10moles  of KMnO_4

Mass of KMnO_4=moles\times {\text {Molar mass}}=0.10moles\times 158g/mol=15.8g

Thus 15.8 g of KMnO_4 will be required to produce 1.60 grams of O_2

5 0
3 years ago
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