Answer:
0.010g of C-14 would be later after 50,000 years
Explanation:
The kinetics of radioactive decay follows the equation:
Ln (N / N₀) = -kt
<em>Where N could be taken as mass after time t, </em>
<em>N₀ initial mass = 4.30g;</em>
k is rate constant = ln 2 / t(1/2)
<em>= ln 2 / 5730years = 1.2097x10⁻⁴ years ⁻¹</em>
<em />
Replacing:
Ln (N / 4.30g) = -1.2097x10⁻⁴ years ⁻¹ * 50000 years
N / 4.30 = 2.36x10⁻³
N =
<h3>0.010g of C-14 would be later after 50,000 years</h3>
Answer:
2.28 moles of water are needed
Explanation:
We need to determine the reaction, to solve this:
The reactans are H₂O and Mg₃N₂
The products are: MgO and NH₃
Equation: 3H₂O + Mg₃N₂ → 3MgO + 2NH₃
We need to determine how many moles are those ammonia molecules, so we apply the NA (6.02×10²³)
Conversion factor 9.17×10²³ molecules . 1 mol/ NA = 1.52 moles
Ratio is 2:3. 2 moles of ammonia can produced by 3 moles of water
Then, 1.52 moles of ammonia must be produced by (1.52 . 3) / 2 = 2.28 moles of water
Answer:
dragon fly larvae, beetles, fish, pelican
Explanation:
Answer:
1 0 0 1- forbidden
1 3 3 1/2- forbidden
3 2 3 -1/2- forbidden
0 1 0 1/2- forbidden
2 1 -1 0- forbidden
2 -1 -1 1/2- forbidden
Explanation:
1 0 0 1 is a forbidden combination because the spin quantum number can only take values of ±1/2.
1 3 3 1/2 is forbidden because it refers to an electron in a 1f orbital which does not exist.
3 2 3 -1/2 refers to an electron in a 3d orbital. However, the allowed values of the magnetic quantum number are only -2,-1,0,1,2. Hence 3d orbital cannot have a magnetic quantum number of 3.
No electron can be found in an n=0 energy level hence 0 1 0 1/2 does not exist.
Given 2 1 -1 0, the combination is forbidden because the allowed values of the spin quantum number are only ±1/2.
For 2 -1 -1 1/2, this combination is forbidden because the values of the orbital quantum number must be positive integers and not negative integers.
